Answer:
Step-by-step explanation:
Solution,
The perimeter of a triangle=Sum of all sides

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Dimensions are length 20 meter and width 14 meter
<em><u>Solution:</u></em>
Let "a" be the length of rectangle
Let "b" be the width of rectangle
Given that,
<em><u>A rectangle has width that is 6 meters less than the length</u></em>
Width = length - 6
b = a - 6
The area of the rectangle is 280 square meters
<em><u>The area of the rectangle is given by formula:</u></em>

<em><u>Substituting the values we get,</u></em>

<em><u>Solve the above equation by quadratic formula</u></em>



Since, length cannot be negative, ignore a = -14
<em><u>Thus solution of length is a = 20</u></em>
Therefore,
width = length - 6
width = 20 - 6 = 14
Thus dimensions are length 20 meter and width 14 meter
12 | 12
— — —
20 | 6
ab = 2 * 6 = 12
4b/2 = (4 * 6) / 2 = 24 / 2 = 12
a^3 + 2b = 2^3 + 2 * 6 = 8 + 2 * 6 = 8 + 12 = 20
b^2 / (4 + a) = 6^2 / (4 + 2) = 6^2 / 6 = 36 / 6 = 6
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Answer:-8
Step-by-step explanation:
I honestly don’t understand this but I think I could help