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shutvik [7]
3 years ago
7

Le ways

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0

<em>the answer 3.15</em>

<em>Step-by-step explanation:</em>

<em>because 45x7=315</em>

<em>if I am wrong i am soury</em>

<em />

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The surface area of a cone is 54 square inches. What is the surface area of a similar cone that is three times as large?
12345 [234]

<u>Given</u>:

Given that the surface area of the cone is 54 square inches.

We need to determine the surface area of the cone that is similar to the cone three times large.

<u>Surface area of the similar cone:</u>

Let us determine the surface area of the similar cone.

The surface area of the similar cone can be determined by multiplying the surface area of the cone by 3. Because it is given that the similar cone is three times large.

Thus, we have;

SA = 3 \times 54

SA=162

Thus, the surface area of the similar cone is 162 square inches.

6 0
3 years ago
Help me plzzzzzzzzzzzzzzzzzz.
Sophie [7]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
A model rocket is launched with an initial velocity of 200 ft per second. The height h, in feet, of the rocket t seconds after t
Solnce55 [7]

Answer:

2.10 s, 10.40 s.

Step-by-step explanation:

We know that the height of the rocket is given by the function:

h=-16t^2+200t

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

350=-16t^2+200t

The last is a quadratic equation, which can be put in the form at^2+bt+c=0 and solved applying the formula:

t=\frac{-b+-\sqrt{b^2-4ac} }{2a}

So, let's put the equation on the form at^2+bt+c=0 adding 16t^2 and subtracting 200t to each side of the equation; the result is:

16t^2-200t+350=0

So, we note that a=16, b=-200, and c=350.

Then,

t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10

t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

4 0
3 years ago
The 17th term of an Arithmetic sequence is 51. If the commons difference is 7, what is the first term ?
vovikov84 [41]

Answer:

The first term is:

  • a_1=-61

Step-by-step explanation:

The arithmetic sequence is defined by

a_n=a_1+\left(n-1\right)d

where

a_1 is the first term

d is the common difference

as

the 17th term of an arithmetic sequence is 51.

i.e. a_{17}=51

so

a_n=a_1+\left(n-1\right)d

a_{17}=a_1+\left(17-1\right)d        

51=a_1+\left(17-1\right)7         ∵ n = 17, a_{17}=51 , d=7

a_1+112=51                   ∵ \left(17-1\right)\cdot \:\:7=112

a_1=-61

Therefore, the first term is:

  • a_1=-61
8 0
3 years ago
Find the volume of a cube with edges measuring 9ce
IceJOKER [234]

Answer:

<h2>V = 729</h2>

Step-by-step explanation:

The formula of a volume of a cube with an edge <em>a</em>

<h3>V = a³</h3>

We have <em>a </em>=<em> </em>9 . Substitute:

<h3>V = 9³ = 9 · 9 · 9 = 729</h3>
6 0
4 years ago
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