Question

Pls help me. To be submitted tomorrow​

Answer 1

Answer:

$\frac{1}{7}$

Step-by-step explanation:

Given

tanx = $\frac{3}{4}$ = $\frac{opposite}{adjacent}$

This is a 3- 4- 5 right triangle with hypotenuse = 5, then

cosx = $\frac{adjacent}{hypotenuse}$ = $\frac{4}{5}$

sinx = $\frac{opposite}{hypotenuse}$ = $\frac{3}{5}$

Then

$\frac{cosx-sinx}{cosx+sinx}$

= $\frac{\frac{4}{5}-\frac{3}{5} }{\frac{4}{5}+\frac{3}{5} }$

= $\frac{\frac{1}{5} }{\frac{7}{5} }$

= $\frac{1}{5}$ × $\frac{5}{7}$

= $\frac{1}{7}$