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alexandr1967 [171]
3 years ago
15

A construction company uses the function f(x), where x is the number of people working on a project, to model the amount of mone

y it spends to complete a project. What would a reasonable domain be?
All integers
Real numbers
Positive real integers
Positive integers
Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0

Answer:

  • Positive integers

Step-by-step explanation:

The domain is the people and the range is the money spent

People would be counted as positive integers, only the last answer choice considers this.

<u>So the answer is:</u>

  • Positive integers
Neko [114]3 years ago
6 0

<em><u>Answer:</u></em>

<em><u>Please use "^" to denote exponentiation:  f(x) = x^2 + 3x + 5. </u></em>

<em><u> </u></em>

<em><u>Because this is a polynomial, the domain consists of the set of all real numbers. </u></em>

<em><u></u></em>

<em><u>Step-by-step explanation:</u></em>

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Art [367]

Answer:

The height of the parallelogram relates to the height of the circle because it is equal to the radius of the circle. The height goes from the circumference to the point of any section of the circle. I hope this helps.

Step-by-step explanation:

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Step-by-step explanation:

The area of a triangle is

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A = 1/2 (14)*7

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sam is 12 in four years his age will be 2/3 the age of his cousin like how old will luke be in two years
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3 years ago
SHOW YOUR WORK!!<br><br> What is the distance between point A (-3, -2) and Point B (4, -7)?
gulaghasi [49]

Answer: \bold{\sqrt{74}}

<u>Step-by-step explanation:</u>

\text{Use the distance formula: }d_AB=\sqrt{(x_A-x_B)^2+(y_A-y_B)^2}\\where\ (X_A, y_A)=(-3, -2)\\and\ (x_B,y_B)=(4, -7)\\\\\\d_AB=\sqrt{(-3-4)^2+[-2-(-7)]^2}\\\\.\quad =\sqrt{(-7)^2+(5)^2}\\\\.\quad =\sqrt{49+25}\\\\.\quad =\boxed{\sqrt{74}}

3 0
4 years ago
Write the equation for a parabola with a focus at (6,-4) and a directrix at y= -7
shtirl [24]

Given:

The focus of the parabola is at (6,-4).

Directrix at y=-7.

To find:

The equation of the parabola.

Solution:

The general equation of a parabola is:

y=\dfrac{1}{4p}(x-h)^2+k                  ...(i)

Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.

The focus of the parabola is at (6,-4).

(h,k+p)=(6,-4)

On comparing both sides, we get

h=6

k+p=-4                            ...(ii)

Directrix at y=-7. So,

k-p=-7                            ...(iii)

Adding (ii) and (iii), we get

2k=-11

k=\dfrac{-11}{2}

k=-5.5

Putting k=-5.5 in (ii), we get

-5.5+p=-4

p=-4+5.5

p=1.5

Putting h=6, k=-5.5,p=1.5 in (i), we get

y=\dfrac{1}{4(1.5)}(x-6)^2+(-5.5)

y=\dfrac{1}{6}(x-6)^2-5.5

Therefore, the equation of the parabola is y=\dfrac{1}{6}(x-6)^2-5.5.

4 0
3 years ago
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