Answer:
Step-by-step explanation:
Even numbers are those that can be divided by 2.
3440 and 7802
Odd numbers are the rest
4893, 1451 and 6645
Smallest to largest
1451, 3440, 4893, 6645 and 7802
Sum of even numbers
3440+7802= 11242 divided by 2(there are only 2 numbers)
11242 ÷ 2 = 5621
You could make a small (easily repaired) leak and watch it for the amount of time you need to conclude what you need to.
How can i put the number 103,727,495 in expanded form
You can put the number 103, 727,495 in expanded form by:
<span><span>1.
</span>100, 000, 000 + 3,000, 000 + 700,000 + 20, 000 +
7, 000 + 400 + 90 + 5</span>
Which in words is.
<span><span>1.
</span>One hundred three million seven hundred twenty
seven thousand four hundred ninety-five </span>
Answer:
k=8
Step-by-step explanation:
We can solve using the slope formula
m= (y2-y1)/(x2-x1)
3/5 = (k-2)/(4- -6)
3/5 = (k-2)/(4+6)
3/5 = (k-2)/10
Multiply each side by 10
10*3/5 = (k-2)/10 *10
6 = k-2
Add 2 to each side
6+2 = k-2+2
8 = k
-- The smallest perimeter you can make with a certain area
is a circle.
-- The NEXT smallest perimeter with the same area is a square.
With 1-ft by 1-ft square bricks, the shortest perimeter she could
make would be by using her bricks to make it as square as possible.
Without cutting bricks into pieces, the best she could do would be
(13 bricks) x (3 bricks) .
= (13-ft) x (3-ft)
Perimeter = (2 x length) + (2 x width)
= (2 x 13-ft) + (2 x 3-ft)
= (26-ft) + (6-ft) = 32 feet <== shortest perimeter.
-- Then, the more UNSQUARE you make it, the more perimeter
it takes to enclose the same area. That means Mary has to make
a rectangle as long and skinny as she can.
The longest perimeter she can make (without cutting bricks into
pieces) is (39 bricks) x (1 brick) .
= (39-ft) x (1-ft) .
Perimeter = (2 x length) + (2 x width)
= (2 x 39-ft) + (2 x 1-ft)
= (78-ft) + (2-ft) = 80 feet .
What she'll have then is a brick path, 39 feet long and 1 foot wide,
and when you walk on it, you'll need to try hard to avoid falling off
because it's only 1 foot wide.
