All categories

3 years ago

Please helppppppppppppppppppp :) .

Mathematics

1 answer:

pickupchik [31]3 years ago

7 0

Answer and Step-by-step explanation:

I think this is the correct answer (in picture):

This is because you can either get Heads or Tails, so once you flip it once, you just flip it again and you will get either heads or tails.

#teamtrees #PAW (Plant And Water)

You might be interested in

Convert decimal 7.79 miles into mixed number milesnow

Kryger [21]

7 and 79/100 miles that is the answer

8 0

3 years ago

You use a wedge that has a width of 2 cm and a slope length of 5.5 cm. What is the mechanical advantage of this wedge?

PIT_PIT [208]

Answer:

Option B. 2.75

Step-by-step explanation:

It has been given in the question that a wedge has a width of 2 cm and a slope of 5.5 cm.We have to calculate the mechanical advantage of the given wedge.

We know the formula to calculate the mechanical advantage of the wedge

Mechanical advantage = Length of slope/Thickness of the widest end

= 5.5÷2 = 2.75

Therefore the answer is option B. 2.75

6 0

3 years ago

Read 2 more answers

Annie wants to use the problem-cause-solution order to organize a persuasive speech to reduce violence on campus. she begins by

ollegr [7]

The possible next step that Annie should use in the persuasive speech is to discuss the lack of street lamps and campus security as causes of the problem.

<h3>What is a persuasive speech?</h3>

It should be noted that a persuasive speech simply means a speech that is used to convince an individual to agree to a particular perspective.

In this case, the possible next step that Annie should use in the persuasive speech is to discuss the lack of street lamps and campus security as causes of the problem.

Learn more about speech on:

brainly.com/question/25887038

7 0

2 years ago

In investing $6,200 of a couple's money, a financial planner put some of it into a savings account paying 4% annual simple inter

ddd [48]

Answer:

$ 2,600 was invested at 4% and $ 3,600 was invested at 9%.

Step-by-step explanation:

Given that in investing $ 6,200 of a couple's money, a financial planner put some of it into a savings account paying 4% annual simple interest, and the rest was invested in a riskier mini-mall development plan paying 9% annual simple interest, and the combined interest earned for the first year was $ 428, to determine how much money was invested at each rate, the following calculation must be performed:

3000 x 0.04 + 3200 x 0.09 = 408

2500 x 0.04 + 3700 x 0.09 = 433

2600 x 0.04 + 3600 x 0.09 = 428

Therefore, $ 2,600 was invested at 4% and $ 3,600 was invested at 9%.

7 0

3 years ago

Mathematical induction, prove the following two statements are true

adelina 88 [10]

Prove:
$1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+n\left(\frac12\right)^{n-1}=4-\dfrac{n+2}{2^{n-1}}$
____________________________________________

Base Step: For n=1:
$n\left(\frac12\right)^{n-1}=1\left(\frac12\right)^{0}=1$
and
$4-\dfrac{n+2}{2^{n-1}}=4-3=1$
--------------------------------------------------------------------------

Induction Hypothesis: Assume true for n=k. Meaning:
$1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}=4-\dfrac{k+2}{2^{k-1}}$
assumed to be true.

--------------------------------------------------------------------------

Induction Step: For n=k+1:
$1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}$

by our Induction Hypothesis, we can replace every term in this summation (except the last term) with the right hand side of our assumption.
$=4-\dfrac{k+2}{2^{k-1}}+(k+1)\left(\frac12\right)^{k}$

From here, think about what you are trying to end up with.
For n=k+1, we WANT the formula to look like this:
$1+2\left(\frac12\right)+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}=4-\dfrac{(k+1)+2}{2^{(k+1)-1}}$

That thing on the right hand side is what we're trying to end up with. So we need to do some clever Algebra.

Combine the (k+1) and 1/2, put the 2 in the bottom,
$=4-\dfrac{k+2}{2^{k-1}}+\dfrac{(k+1)}{2^{k}}$

We want to end up with a 2^k as our final denominator, so our middle term is missing a power of 2. Let's multiply top and bottom by 2,
$=4+\dfrac{-2(k+2)}{2^{k}}+\dfrac{(k+1)}{2^{k}}$

Distribute the -2 and combine the fractions together,
$=4+\dfrac{-2k-4+(k+1)}{2^{k}}$

Combine like-terms,
$=4+\dfrac{-k-3}{2^{k}}$

pull the negative back out,
$=4-\dfrac{k+3}{2^{k}}$

And ta-da! We've done it!
We can break apart the +3 into +1 and +2,
and the +0 in the bottom can be written as -1 and +1,
$=4-\dfrac{(k+1)+2}{2^{(k-1)+1}}$

3 0

3 years ago