All categories

3 years ago

Solve the equation simultaneously. Y=x² + 2x + 1, Y= x²+2x - 2.. Solve for the values of X and Y.

Mathematics

1 answer:

Papessa [141]3 years ago

5 0

The two functions should never intersect.

Since y = y, we can equate the other side of both equations together.

x^2 + 2x + 1 = x^2 + 2x - 2

Rearrange the equation to bring all the terms to one side.

0 = x^2 - x^2 + 2x - 2x - 2 - 1

0 = -3

You can see that does not make sense, so we can conclude that there are no points of intersection between the two functions.

I also graphed the functions. In the first pic you can see that the red is between the blue and they don't intersect. In the second pic I zoomed in so you can see the right side of the graph going up to y = 600 and the red is still between the blue.

You might be interested in

Can you please help me in this question :o)

Maurinko [17]

Which question do you need help on?

6 0

3 years ago

Suppose I have an urn with 9 balls: 4 green, 3 yellow and 2 white ones. I draw a ball from the urn repeatedly with replacement.

Mrrafil [7]

Answer:

$E(X_n)=\frac{2(n-1)}{27}$

$E(y)=\frac{14}{9}$

Step-by-step explanation:

From the question we are told that:

Sample size n=9

Number of Green $g=4$

Number of yellow $y=4$

Number of white $w=4$

Probability of Green Followed by yellow P(GY) ball

$P(GY)=\frac{4}{9}*\frac{3}{9}$

$P(GY)=\frac{4}{27}$

Generally the equations for when n is even is mathematically given by

$Probability of success P(S)=\frac{4}{27}$

$Probability of Failure P(F)=\frac{27-4}{27}$

$Probability of Failure P(F)=\frac{23}{27}$

Therefore

$E(X_n)=\frac{n}{2}*P$

$E(X_n)=\frac{n}{2}*\frac{4}{27}$

$E(X_n)=\frac{2n}{27}$

Generally the equations for when n is odd is mathematically given by

$\frac{n-1}{2}$

$E(X_n)=\frac{n-1}{2}*\frac{4}{27}$

$E(X_n)=\frac{2(n-1)}{27}$

Probability of drawing white ball

$P(w)=\frac{2}{9}$

Therefore

$E(w)=\frac{1}{p}$

$E(w)=\frac{1}{\frac{2}{9}}$

$E(w)=\frac{9}{2}$

Therefore

$E(y)=[E(w)-1]\frac{4}{9}$

$E(y)=[\frac{9}{2}-1]\frac{4}{9}$

$E(y)=\frac{14}{9}$

5 0

3 years ago

HALP PLS NO LINKS OR FILES PLS<br> SCREENSHOT BELOW!!!

Sidana [21]

Answer:

12 and 13

Step-by-step explanation:

7 0

3 years ago

(2x + 3) •x • (4x + 1)

Virty [35]

Answer:

If your trying to simplify then your answer would be $8x^{3} + 14x^{2} +3x$

6 0

3 years ago

What do the solutions of a quadratic equation represent graphically? What is the maximum number of solution(s) given by solving

astra-53 [7]

Answer:

The solutions of a quadratic equation on a graph is the point where the graph cuts across the x and y axes. The maximum number of solutions given by solving a quadratic equation is 2 solutions because the maximum power in a quadratic equation is power 2

8 0

3 years ago

Solve the equation simultaneously. Y=x² + 2x + 1, Y= x²+2x - 2.. Solve for the values of X and Y.​

Solve the equation simultaneously. Y=x² + 2x + 1, Y= x²+2x - 2.. Solve for the values of X and Y.