Find the distance between the points given.<br> (-3,-4) and (0,0)

The number 0.6064 represents the area under the standard normal curve below a particular z-score. What is the Z-score? Express t

Anastasy [175]

P(z < x) = 0.6064 - 0.5 = 0.1064

From the normal distribution table
P(z < 0.27) = 0.1064

Therefore the z-score is 0.27

I can't explain it very well for you, sorry.

4 0

2 years ago

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Increase 30g by 10%, please explain :))

Grace [21]

Answer:

33g

Step-by-step explanation:

10% of 30g is 3g so add 30g to 3g and you get 33g.

7 0

2 years ago

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Two trains leave stations 560 miles apart at the same time and travel toward each other. One train travels at 90 miles per hour

lana [24]

Answer: the two trains will meet in 2.8 hours

Step-by-step explanation:

Step 1

Speed of train A = 90mph

Speed of train B = 110 mph

Since both trains are travelling towards each other , their effective speed will be= 90 mph + 110mph= 200mph

Step 2

we know that Speed = distance / time

therefore Time = Distance / speed

Distance = 560 miles

Speed = 200 mph

Time = 560miles / 200mph

2.8 hours

5 0

2 years ago

Which equation is true when r = 7 ?

jeka57 [31]

Answer:

7 = 49 ÷ r

Step-by-step explanation:

To find the equation that is true when r = 7, we need to find a number after the equals sign that is a multiple of 7.

Multiples of 7:

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77...

Therefore, the only answer option in which the number after the equals sign is a multiple of 7 is:

7 = 49 ÷ r

To prove this, input r = 7 into each of the equations:

6 = 30 ÷ r

⇒ 6 = 30 ÷ 7

⇒ 6 ≠ 4.285... ← incorrect!

7 = 54 ÷ r

⇒ 7 = 54 ÷ 7

⇒ 7 ≠ 7.714... ← incorrect!

7 = 49 ÷ r

⇒ 7 = 49 ÷ 7

⇒ 7 = 7 ← correct!

9 = 72 ÷ r

⇒ 9 = 72 ÷ 7

⇒ 9 ≠ 10.285... ← incorrect!

8 0

2 years ago

Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar

Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

$((a, b), (c, d))\in R$

Where $R$ is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

$\forall a \in A \Rightarrow (a,a) \in R$

Here we need to prove:

$\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R$

As per the given relation:

$((a,b), (a,b) ) \Rightarrow ab =ab$ which is true.

$\therefore$ R is reflexive.

2. Now, let us check symmetric property:

Symmetric property means:

$\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R$

Here we need to prove:

$\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R$

As per the given relation:

$((a,b),(c,d)) \in R$ means $ad = bc$

$((c,d),(a,b)) \in R$ means $cb = da\ or\ ad =bc$

Hence true.

$\therefore$ R is symmetric.

3. R to be transitive, we need to prove:

$if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R$

$((a,b),(c,d)) \in R$ means $ad = cb$ .... (1)

$((c,d), (e,f)) \in R$ means $fc = ed$ ...... (2)

To prove:

To be $((a,b), (e,f)) \in R$ we need to prove: $fa = be$

Multiply (1) with (2):

$adcf = bcde\\\Rightarrow fa = be$

So, R is transitive as well.

Hence proved that R is an equivalence relation.

8 0

3 years ago

Find the distance between the points given. (-3,-4) and (0,0)