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3 years ago

Find the distance between the points given. (-3,-4) and (0,0)

Mathematics

1 answer:

cestrela7 [59]3 years ago

3 0

Answer: 5 Units

Step-by-step explanation:

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The ratio of the measures of the sides of a triangle is 9:12:5. If the perimeter of the triangle is 130 feet find the measures o

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45 feet, 60 feet, 25 feet

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3 years ago

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The product of 5 more than a number, and 4

Lyrx [107]

Answer:

x + 5 * 4

In this problem we have to transfer the expression from verbal to mathematical language. Which would be:

x + 5 * 4

"x" represents "a number"

"5 more than a number" is represented by "x + 5"

"the product of" is indicating a multiplication, which is represented by "*"

Hope it helped,

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Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

Put $(x,y)=(1,1)$

$\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9$

This is true.

So, the point $(1,1)$ satisfies the equation $\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

So, point H is $(1,1)$ .

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3 years ago

What is the value of y in the equation 5x+2y=20 when x=0.3

MakcuM [25]

5 multiplied by .3 is 1.5
1.5 + 18.5 = 20.
y = 9.25

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3 years ago

Evaluate the expression for x = 3.4, x = 7.6

Scrat [10]

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2 years ago