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3 years ago

Slope=4,passing through (7,4)

Mathematics

1 answer:

barxatty [35]3 years ago

7 0

Answer:

if ur trying finding the y-intercept it's -24

Step-by-step explanation:

slope- intercept form is y=mx+b we know m is 4 (7,4) 7 is the x 4 is the y ...

then you plug them in and we know 4 times 7 is 28 and then 4-s8 is -24

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What is the quotient of 2 1/4 and 5/8?

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A family’s vacation destination is 850 miles from their home. They travel by car 6 hours on the first day of their trip. Their a

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Answer:A family’s vacation destination is 850 miles from their home. They travel by car 6 hours on the first day of their trip. Their average speed is 45 miles per hour. The next day they travel 7 hours, averaging the same speed. How many miles are left for the family to travel?

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4 years ago

Suppose that $2000 is invested at a rate of 2.6 %, compounded quarterly Assuming that no withdrawals are made the amount after 8

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3 years ago

Which equation correctly applies the distributive property?

Step2247 [10]

Answer: Only Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Distributive property states that

$a\times (b+c+d)=a\times b+a\times c+a\times d$

According to option 'C', we get that

a = 0.5

b = 0.5

c = 0.3

d = 0.2

So, it is written as

$0.5(0.5+0.3+0.2)=0.5\times 0.5+0.5\times 0.3+0.5\times 0.2$

Hence, only Option 'C' is correct.

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3 years ago

If we assume the population of Grand Rapids is growing at a rate of approximately 4% per decade, we can model the population fun

saw5 [17]

Answer:

The average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

Step-by-step explanation:

The given function is

$P(t)=181843(1.04)^{(\frac{t}{10})}$

where, P(t) is population after t years.

At t=5,

$P(5)=181843(1.04)^{(\frac{5}{10})}=185444.20$

At t=6,

$P(6)=181843(1.04)^{(\frac{6}{10})}=186172.95$

At t=7,

$P(7)=181843(1.04)^{(\frac{7}{10})}=186904.57$

At t=8,

$P(8)=181843(1.04)^{(\frac{8}{10})}=187639.06$

At t=9,

$P(9)=181843(1.04)^{(\frac{9}{10})}=188376.44$

At t=10,

$P(10)=181843(1.04)^{(\frac{10}{10})}=189116.72$

The rate of change of P(t) on the interval $[x_1,x_2]$ is

$m=\frac{P(x_2)-P(x_1)}{x_2-x_1}$

Using the above formula, the average rate of change of the population on the intervals [ 5 , 10 ] is

$m=\frac{P(10)-P(5)}{10-5}=\frac{189116.72-185444.20}{5}=734.504$

The average rate of change of the population on the intervals [ 5 , 9 ] is

$m=\frac{P(9)-P(5)}{9-5}=\frac{188376.44-185444.20}{4}=733.06$

The average rate of change of the population on the intervals [ 5 , 8 ] is

$m=\frac{P(8)-P(5)}{8-5}=\frac{187639.06-185444.20}{3}=731.62$

The average rate of change of the population on the intervals [ 5 , 7 ] is

$m=\frac{P(7)-P(5)}{7-5}=\frac{186904.57-185444.20}{2}=730.185$

The average rate of change of the population on the intervals [ 5 , 6 ] is

$m=\frac{P(6)-P(5)}{6-5}=\frac{186172.95-185444.20}{1}=728.75$

Therefore the average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

7 0

4 years ago