Answer:
13π/4 , 21π/4, -3π/4, -11π/4
Step-by-step explanation:
Coterminal Angles are angles which share the same initial side and terminal sides.
To find coterminal angles, simply add or subtract 360° or 2π to each angle, depending on whether the given angle is in degrees or radians.
5π/4 =(4π/4)+(π/4)
Our Angle 5π/4 is in the 3rd quadrant and exceeds π radians by (π/4) radians, or 45° angular measure.
The 2 positive co-terminal angles would be:
Adding 2π
5π/4 + 2π = 13π/4
Adding another 2π
5π/4 + 2π +2π = 21π/4
The two negative co-terminal angles would be:
Subtracting 2π
5π/4 - 2π = -3π/4
Subtracting another 2π
5π/4 - 2π -2π = -11π/4
The coterminal angles are:
13π/4 , 21π/4, -3π/4, -11π/4
H=3.7
Then 0.8+h=0.8+3.7
=4.5
Answer:
length of chord is 6cm
Step-by-step explanation:
Here, we are to calculate the length of the chord.
It should be understood that the chord has a length of 0.8cm from the center of the circle of radius 3cm, thereby forming two right-angled triangles with the radius 3cm being the hypotenuse of each and 0.8cm being the height of each.
Now, the chord is divided into 2 by this height dropping from the center of the circle. To calculate the first half, we use Pythagoras’ theorem with 3cm being hypotenuse and 0.8cm being the other side.
mathematically;
3^2 = 0.8^2 + l^2
9 = 0.64 + l^2
l^2 = 9-0.64
l^2 = 8.36
l = √(8.36)
l = 2.89 approximately
The length of the chord would be 2l = 2 * 2.89 = 5.78 cm which is 6cm to the nearest length
Answer:
ME=0.014
Sample Proportion=0.725
Step-by-step explanation:
-The margin of error is defined as the percentage by which obtained results differ from the real population value.
-It is calculated as half the difference between the confidence interval levels:
![ME=\frac{1}{2}[CI_u-CI_l]\\\\=0.5[0.739-0.711]\\\\=0.014](https://tex.z-dn.net/?f=ME%3D%5Cfrac%7B1%7D%7B2%7D%5BCI_u-CI_l%5D%5C%5C%5C%5C%3D0.5%5B0.739-0.711%5D%5C%5C%5C%5C%3D0.014)
Hence, the margin of error is 0.014
-The sample proportion is mathematically half the sum of the confidence intervals:
![ME=\frac{1}{2}[CI+u-CI_l]\\\\=0.5[0.739+0.711]\\\\=0.725](https://tex.z-dn.net/?f=ME%3D%5Cfrac%7B1%7D%7B2%7D%5BCI%2Bu-CI_l%5D%5C%5C%5C%5C%3D0.5%5B0.739%2B0.711%5D%5C%5C%5C%5C%3D0.725)
Hence, the sample proportion is 0.725