A pet pharmaceutical company releases a new treatment, claiming to control fleas in cats for an average of 60 days per dose.

I NEED ANSWER SUPER BAD PLEASE!!!!!!!!!!!What is the greatest integer less than 100 for which the greatest common divisor of tha

PtichkaEL [24]

Answer:

92

Step-by-step explanation:

We will list out the numbers which are factors of 12. They include:

1, 2, 3, 4, 6, 12.

We need to get the highest number that has its greatest factor to be 4. It means that 6 and 12 cannot divide it.

To do this, we will write out the multiples of 4. They include:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88,92,96.

We will have to choose the highest number which only 4 can divide and 6 and 12 cannot divide.

Since we are looking for the largest, We can try dividing all the numbers by 4, 6, and 12 starting from 96.

We will quickly see that 4 can divide 92 but 6 and 12 cannot.

This gives us 92 as the answer.

4 0

2 years ago

State the common difference for the given A.P.3/2,1/2,-1/2,-3/2,......

a_sh-v [17]

Answer:

-1

Step-by-step explanation:

The common difference is the constant amount of change between the numbers in an arithmetic sequence.

To find the common difference, you take the last term and subtract it by the previous term.

$\frac{-3}{2} - \frac{-1}{2} =-1$

8 0

2 years ago

The line A bus arrives at the stop every 25 min. and the line B bus arrives every 15 min. Both arrive at the bus stop at 1 pm. A

worty [1.4K]

Answer:

love you sweety

Step-by-step explanation:

love u sweety sweety

6 0

3 years ago

Simplify the rational expression. State any restrictions on the variable.

ExtremeBDS [4]

we are given

$\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}$

Firstly, we will factor numerators and denominators

$\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-6)(n^2-4)}{(n^2-3)(n^2-6)}$

we can see that

n^2 -6 is factor on both numerator and denominator

so, it will get cancelled

and n^2 -6 can not be equal to 0

so, one of restriction is

$n^2-6\neq 0$

$n\neq -+ \sqrt{6}$

we can simplify it

$\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-4)}{(n^2-3)}$

we know that denominator can not be zero

$n^2-3\neq 0$

$n\neq -+ \sqrt{3}$

so, option-B.......Answer

3 0

3 years ago

I thought i had the right answer, but it was wrong. So anyone want to to help me with this? Please dont steal points. 7 points e

SSSSS [86.1K]

Answer:16 dollars per shirt

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers