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MA_775_DIABLO [31]
3 years ago
10

Please help with letter b.

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0
Around 58%. It is safe to believe that about the same percentage of students in the school have pets. This is because they are split in groups of 10 and they can be represented as part of a whole, in this case the surveyed students are part and the whole school is the school.
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if i measure a hypotenuse and i get 11 and then i double check my work by doing the a squared + b squared = c squared method and
RoseWind [281]
Hi there!

Sometimes, like you said, you might don't get the exact answer when you justified your answer. In this case, you need to take the nearest number. So if you got 11 then 12 is the nearest number, just go for it.

Or go back and start over and see if you didn't miss anything.


I hope this helps!
5 0
3 years ago
6)
Dvinal [7]

Answer:

It has to be x - 9= 27

so it can be x=36

6 0
3 years ago
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What are the special right triangle measures?
erik [133]
The hypotenuse is 2x, the base is x*sqrt(3) and the left base if x
5 0
3 years ago
The Great Pyramid in Giza, Egypt, is a square pyramid. The dimensions of the pyramid at the time of its completion are shown in
ryzh [129]

Answer:

Area of square pyramid is 153883.8\ m^{2}.

Step-by-step explanation:

Diagram of the given scenario is shown below,

Given that,

The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is 154 \ m^{2}. The side of the square is 230 \ m and The height of each triangle is 187 \ m.

So,    Area of Square shape  = 154 \ m^{2}

         Side of square = 230 \ m

      Height of each triangle = 187 \ m

Finding the Height of triangular shape which is here known as slant height.

 In Δ ABO, applying Right angle pythagorean Theorem,

                  Base (BO) =  \frac{230}{2} = 115\ m

                Height (AO) = 187\ m

Now,      

∴                   AB^{2} = AO^{2} \ + \ BO^{2}

⇒                    AB= \sqrt{AO^{2} \ + \ BO^{2}  }

⇒                   AB= \sqrt{187^{2} \ + \ 115^{2}  }

⇒                   AB= \sqrt{34969 \ + \ 13225   }

⇒                   AB= 219.53 \ m

Then,

           Area of square pyramid = area \ of \ square + \ 4\times area \ of \ traiangle

                                                   = side\times side + 4\times\frac{1}{2}\times AB\times Base  

                                                   = 230\times 230 \  + 2\times 219.53\times 230

                                                   = 52900 + 100983.8

                                                   = 153883.8 \ m^{2}

Hence, Area of square pyramid is 153883.8\ m^{2}.

                   

6 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST<br><br><br>download pdf to see question
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Answer:

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