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Tresset [83]
3 years ago
14

In the diagram below, line segment AC is the perpendicular bisector of line segment EF. Is line segment EF the perpendicular bis

ector of line segment AC? Explain how you know

Mathematics
1 answer:
Mama L [17]3 years ago
8 0

Answer:

Not necessarily. If picture is drawn to scale, no.

Step-by-step explanation:

Line segment EF is certainly perpendicular to line segment AC, but we don't know if it bisects or not.

If the picture isn't drawn to scale, there is no way to know if EF is a perpendicular bisector to AC or not because we do not know if AD = CD.

If the picture is drawn to scale, EF is not a perpendicular bisector to AC because we can see that AD ≠ CD and therefore EF cannot be a perpendicular bisector.  

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For ...

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2(a^{b})^3+(a^b)^2+(a^b)=2x^3+x^2+x

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Option A

Step-by-step explanation:

Given expression:

  • 3x² - 10x - 8

<u>Option A</u>

⇒ (x - 4)(3x + 2)

⇒ (x × 3x) + (2 × x) + (-4 × 3x) + (-4 × 2)

⇒ (3x²) + (2x) + (-12x) + (-8)

⇒ 3x² + 2x - 12x - 8

⇒ 3x² - 10x - 8

3x² - 10x - 8 = 3x² - 10x - 8 (Yes!)

<u>Option B</u>

⇒ (3x - 4)(x - 2)

⇒ (3x × x) + (3x × -2) + (-4 × x) + (-4 × -2)

⇒ (3x²) + (-6x) + (-4x) + (8)

⇒ 3x² - 6x - 4x + (8)

⇒ 3x² - 10x + 8

3x² - 10x - 8 = 3x² - 10x + 8 (No!)

<u>Option C</u>

⇒ (3x - 4)(x + 2)

⇒ (3x × x) + (3x × 2) + (-4 × x) + (-4 × 2)

⇒ (3x²) + (6x) + (-4x) + (-8)

⇒ 3x² + 6x - 4x - 8

⇒ 3x² + 2x - 8

3x² - 10x - 8 = 3x² + 2x - 8 (No!)

<u>Option D</u>

⇒ (3x - 2)(x - 4)

⇒ (3x × x) + (3x × -4) + (-2 × x) + (-2 × -4)

⇒ (3x²) + (-12x) + (-2x) + (8)

⇒ 3x² - 12x - 2x + 8

⇒ 3x² - 14x + 8

3x² - 10x - 8 = 3x² - 14x + 8 (No!)

Since the expression of option A has the same value as the given expression, option A is correct.

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2 years ago
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