Answer:
the answer is "AB"
Step-by-step explanation:
I plugged it into photomath
F=\dfrac{9}{5}C+32\\\\A.\\\dfrac{9}{5}C+32=F\ \ \ |-32\\\\\dfrac{9}{5}C=F-32\ \ \ |\cdot\dfrac{5}{9}\\\\C=\dfrac{5}{9}(F-32)
B.\\F=212\to C=\dfrac{5}{9}(212-32)=\dfrac{5}{9}\cdot180=100\\\\212^oF=100^oC
C.\\F=80\to C=\dfrac{5}{9}(80-32)=\dfrac{5}{9}\cdot48\approx26.7\\\\80^oF\approx26.7^oC
Answer:
72
Step-by-step explanation:
Answer:
a) The length of segment AC is approximately 5.83 centimeters.
b) The angle ACD is approximately 34.5º.
Step-by-step explanation:
a) Since
, the length of segment
is determined by Pythagorean Theorem, that is:


The length of segment AC is approximately 5.831 centimeters.
b) Since
, the length of segment
is determined by this Pythagorean identity:


The angle ACD is determined by the following trigonometric expression:





The angle ACD is approximately 34.448º.
Hey there! :)
Answer:
(3.5, -1).
Step-by-step explanation:
Use the midpoint formula to solve this problem:

Plug in the coordinates given:

Simplify:

Therefore, the coordinates of the mid-point are:
(3.5, -1).