Answer:
There is no convincing evidence at α = 0.10 level that the average vertical jump of students at this school differs from 15 inches.
Step-by-step explanation:
We have to make a hypothesis test to prove the claim that the average vertical jump of students differs from 15 inches.
The null and alternative hypothesis are:
The significance level is 0.10.
The sample mean is 17 and the sample standard deviation is 5.37.
The degrees of freedom are df=(20-1)=19.
The t-statistic is:
The two-sided P-value for t=1.67 is P=0.11132.
This P-value is bigger than the significance level, so the effect is not significant. The null hypothesis can not be rejected.
There is no convincing evidence at α = 0.10 level that the average vertical jump of students at this school differs from 15 inches.
Answer:
Marry = $17
Ravi = $11
Alan = $34
Step-by-step explanation:
Let us assume
Mary be X
Ravi be Y
Alan be Z
So, the equation in total is
X + Y + Z = 62
It is given that
X = Y + 6
Z = 2X
Now we put the Z value in the total equation, so it would be
X + Y + 2X = 62
3X + Y = 62 .................................... (1)
And can we write
X = Y + 6
X - Y = 6 ................................. (2)
Now substitution these two equations,
3X + Y = 62
X - Y = 6
2X = 68
X = $17
So, Z = 2 × 17 = $34
And, Y
$17 + Y + $34 = $62
So, Y = $11
There are several information's already given in the question. Based on those information's the answer can be easily deduced.
Number of days in the year 2008 = 366
Number of traffic collisions in the year 2008 = 197214
Then
Number of t<span>raffic collision related injuries per day = 197214/366
= 538.84
= 540
</span><span>This works out to 540 per day. The correct option is option "C".</span>
Answer:
No we can consider A as single event. See the explanation below
Step-by-step explanation:
Let's define the event A as:
A=" Select a 4 from a standard deck of 52 cards"
We know that in a standard deck we have 4 different types of 4, spade, heart, diamond and club.
And by definition of simple event we need to have just one possible outcome in the experiment, and on this case we have 4 possible options for event A, so for this reason the event A can't be considered as simpl event.
Answer:
2x+23
Step-by-step explanation:
