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eduard
3 years ago
8

Mr. Jamison will stain the deck in his backyard, the deck has an area of 752.4 sqaure feet. If the deck is 33 feet long how wide

is it? Justify your procedure.
Mathematics
1 answer:
shtirl [24]3 years ago
6 0

answer:The width of the deck is 22.8 feet.

Step-by-step explanation:

Since we have given that

Area of the deck = 752.4 square feet

Length of deck = 33 feet

Let width of deck be 'x'.

Since Deck is in the shape of rectangle.

As we know the formula for "Area of rectangle ":

\begin{gathered}Area=Length\times width\\\\752.4=33\times x\\\\\dfrac{752.4}{33}=x\\\\22.8=x\end{gathered}

Area=Length×width

752.4=33×x

33

752.4

=x

22.8=x

Hence, the width of the deck is 22.8 feet.

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(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid
vekshin1

Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

The number of categories, k = 4

Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

df = 4 -1 - 0 = 3

Let the significance level be, α = 5% = 0.05

For  α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

<u>Observed and expected frequencies of calls for each of the region:</u>

<u>Northeast</u>

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

Observed frequency = 60

It contains 36.7% of the US Population

The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

<u>West</u>

Observed frequency = 46

It contains 23.3% of the US Population

The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}

x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

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3 years ago
Help plsss............
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Answer:

The answer would be $50.

Step-by-step explanation:

$5 per session

They come 10 times

$5 x 10 = $50

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What is the value of x and y
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y equals 70 because you have to subtract 110 from 180 which is a straight line and both sides are the same and x is 40 because 70 plus 70 is 140 and 180 - 140 is 40 so x=40 and y=70

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2x + 5y = −13 3x − 4y = −8
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15x-20y=-40
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