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3 years ago

30 POINTS WILL GIVE BRAINLIEST

Mathematics

1 answer:

bonufazy [111]3 years ago

6 0

12—— IT IS C ———————— thank me…!!!! Laterrrr!!!!

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Solve x: 60 pts if u can figure it out and the first one gets brainiest answer

jenyasd209 [6]

Answer:

11.65

Step-by-step explanation:

3x+99x=102x

1188/102=11.65

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2 years ago

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Lydia writes the equation below with the missing value. She puts in a value in the box and says that equation represent a direct

serious [3.7K]

Answer: she put 0 In The box she would have a direct variation

Step-by-step explanation:

Y=5x-0

Lydia has zeroed, this expression means that it is a direct variation

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3 years ago

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The height of a stack of 12 pennies is 18.24 millimeters. What is the thickness of each penny.

Helga [31]

I’m not great at math so I could easily be wrong, but

I divided the 18.24 millimeters by 12 pennies and got 1.52

So if the pennies are all the same size, each penny should 1.52 millimeters.

To show work:

18.24/12=1.52

4 0

3 years ago

What is the common difference of the sequence below?

vagabundo [1.1K]

Answer:

Step-by-step explanation:

In finding the COMMON DIFFERENCE, subtract the 2nd term and the first term.

a1 = -4

a2 = -2

Let "d" representing the COMMON DIFFERENCE.

d = -2 -(-4)

d = -2 + 4

d = 2

ANSWER:

THE COMMON DIFFERENCE OF THIS SEQUENCE IS 2

3 0

2 years ago

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A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

2 years ago