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3 years ago

Help Geometry help pleasseeee??

Mathematics

1 answer:

Artemon [7]3 years ago

6 0

formula

perimeter:c²=a2+b2

area:A=length x width

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WILL GIVE BRAINLIEST, THANKS, AND 5 STARS! PLEASE HELP ME!

Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

Method 1

Apply Difference of Two Squares Formula: $a^2-b^2=(a+b)(a-b)$

Given $x^2-16=0$

Rewrite 16 as 4²

Therefore, $a^2=x^2$ and $b^2=4^2$

$\implies a = \sqrt{x^2}=x$

$\implies b=\sqrt{4^2} =4$

$\implies x^2-16^2=(x+4)(x-4)$

$\implies (x+4)(x-4)=0$

$\implies (x+4)=0 \implies x=-4$

$\implies (x-4)=0 \implies x=4$

Method 2

Given equation:

$x^2-16=0$

Add 16 to both sides:

$\implies x^2-16+16=0 + 16$

$\implies x^2=16$

Square root both sides:

$\implies \sqrt{x^2}=\sqrt{16}$

$\implies x=\pm4$

Therefore, x = -4, x = 4

6 0

3 years ago

Petrol costs 99p per litre. How much would 47 litres cost?

Radda [10]

Step-by-step explanation:

$99 \times 47 = 517 \times 9 = 4653$

6 0

3 years ago

The quadratic function f(x) has a vertex at (9, 8) and opens upward. If g(x) = 4(x − 8)2 + 9, which statement is true?

IrinaVladis [17]

G(x) would involve a translation left 1 and up 1.

g(x) is written in vertex form, which is

g(x) = a(x-h)²+k, where (h, k) is the vertex. Since
g(x) = 4(x-8)²+9, the vertex is at (8, 9). Comparing this to the vertex of f(x), which is at (9, 8), it is left 1 and up 1.

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3 years ago

zuri bought 8 cupcakes,16chocolate cookies and five peanut butter cookies.How many more cookies will need to buy if he wants 2 d

shtirl [24]

She will need to buy 3 more cookies because 2 dozens is 24. And 16 cookies plus 5 is 21 cookies plus 3 is a dozen cookies which is 24

24=16 chocolate cookies+5 peanut cookies+3 random cookies

6 0

3 years ago

Hey guys my last question please answer :) peace and love guys

Vadim26 [7]

Looking at the problem statement, this question states for us to determine the range of the function that is provided in a graph is. Let us first determine what range is.

Range ⇒ Range is what y-values can be used in the function that is graphed. For example, if a line just goes up and down all the way to negative and positive infinity, then the range would be negative infinity to positive infinity as it includes all of the y-values in it's solutions.

Now moving back to our problem, we can see that we have a vertex at (2, -5) and that the lowest y-values is at y = -5. Therefore the y-values would be anything greater than or equal to -5 and less than infinity because the lines go forever up in the positive-y-direction.

Therefore, the option that would best match the description that we provided would be option B, -5 ≤ y < ∞.

5 0

2 years ago