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3 years ago

What is 70% of 50? explain how you got this answer.

2 answers:

7 0

First, convert the percent into a decimal. You can make any percent into a decimal by moving the % sign two places to the left and making it into a decimal point.

70% = 0.70

In mathematics, if can also mean multiply.

0.70 * 50 = 35

So, 35 is the answer to this question.

Advocard [28]3 years ago

5 0

Ans: 35

70% divided by 100 multiplied by 50

70/100 x 50 = 35

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3 years ago

What is the value of f(-12) if f(x) = 4x - 12

Cerrena [4.2K]

Answer:

-36

Step-by-step explanation:

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2 years ago

HELP!! PLEASE A carpenter is framing a window with wood trim where the length of the window is 9 and 1/3 feet. If the width of t

ohaa [14]

We need the perimeter of the window for framing

The window is in the shape of a rectangle with the height of $9 \frac{1}{3}$ feet and width of $6 \frac{3}{4}$ . The diagram of the shape is shown below

The perimeter of a shape is obtained by adding up the length of all the sides that form the shape.

The perimeter of the window is $9 \frac{1}{3}+9 \frac{1}{3}+6 \frac{3}{4}+6 \frac{3}{4}$ = $18 \frac{2}{3}+12 \frac{6}{4}$

We have two whole numbers 18 and 12 and two fractions $\frac{2}{3}$ and $\frac{6}{4}$

Adding the two fractions that have different denominator
$\frac{2}{3}+ \frac{6}{4} = \frac{8}{12}+ \frac{18}{12}= \frac{26}{12}$ , which is an improper fraction which we can change into a mixed number $2 \frac{1}{6}$

So the perimeter of the window is
$18+12+2 \frac{1}{6} =32 \frac{1}{6}$

and the length of wood needed for the frame is $32 \frac{1}{6}$ feet

4 0

2 years ago

A nursery has two hundred 7-gallon palm trees to sell, consisting of coconut palm trees, saw palmetto palm trees and christmas p

motikmotik

Total number of trees available to be sold = 200

Selling price of coconut palm trees sell (Pco)= $75 each

Selling price of saw palmetto palm trees sell (Pp) = $45 each

Selling price of christmas palm trees (Pch) = $30 each

Number of saw palmetto palm trees (Np) = 3 × Number of christmas palm trees (Nch)

Let number of coconut palm trees be Nco

Total price paid by developer for all the palm trees = 12,300

So Total number of trees = Nco + Np + Nch

⇒ 200 = Nco + 3×Nch + Nch

⇒ 200 = Nco + 4Nch ................ (i)

Total selling price of trees = Sco × Nco + Sp × Np + Sch × Nch

⇒ 12,300 = 75×Nco + 45×Np + 30×Nch

Dividing above equation by 5

⇒ 2,460 = 15Nco + 9Np + 6Nch

Substituting Np = 3Nch in the above equation

⇒ 2,460 = 15Nco + 9 (3Nch) + 6Nch

⇒ 2,460 = 15Nco + 33Nch ................ (ii)

Mutiply (i) with 15 and subtract from (ii)

⇒ 2,460 - 3,000 = 15Nco + 33Nch - 15Nco - 60Nch

⇒ -540 = 33Nch - 60Nch

⇒ -540 = 27Nch

⇒ Nch=20

If Nch = 20, Np = 3×20 = 60

Since Nco + Np + Nch = 200

⇒ Nco = 200 - (80)

⇒ Nco = 120

Hence, the developer purchased 120 coconut palm trees, 20 christmas palm trees and 60 saw palmetto palm trees.

6 0

3 years ago