OK for this question you need to find out how many more post are needed. If you look at the diagram it shows that one side is 50 feet. Now there are two sides that will need post, because the barn side need no more. Now if there are two side both 50 feet, and you need a post every ten feet. How many posts are needed?
Answer:
-0.25 ; 120 seconds 72 seconds
Step-by-step explanation:
Dive rate is constant :
Change in elevation after 8 seconds :
18 feets to 20 feets below
Rate of change = distance / time
(18 - 20) feets / 8 seconds
(-2 / 8) = - 0.25 feets per second
To reach 50.feets :
She needs to cover (50 - 20) = 30 feets
Time = distance / speed ; 30 feets / 0.25 = 120 seconds
<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>
Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get
f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24
So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5
<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5
The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.
So the final answer is C) 3
The answer for your questions is -5