P(z < x) = 0.6064 - 0.5 = 0.1064
From the normal distribution table
P(z < 0.27) = 0.1064
Therefore the z-score is 0.27
I can't explain it very well for you, sorry.
The inverse of this function would be f(x) =
.
You can find the value of any inverse function by switching the f(x) and the x value. Then you can solve for the new f(x) value. The end result will be your new inverse function. The step-by-step process is below.
f(x) =
- 6 ----> Switch f(x) and x
x =
- 6 ----> Add 6 to both sides
x + 6 =
-----> Take the logarithm of both sides in order to get the f(x) out of the exponent
Log(x + 6) = f(x)Log2 ----> Now divide both sides by Log2
= f(x) ----> And switch the order for formatting purposes.
f(x) = 
And that would be your new inverse function.
Answer:
this is my answer
Step-by-step explanation:
The expression P(−1.33<z<1.59) represents the area under the standard normal curve above a given value oz. Use your standard normal table to find the indicated area. Use a sketch of the standard normal curve with the appropriate area shaded to help find the answer.What is the value of P(−1.33<z<1.59) between the given values oz?Express your answer rounded to 4 decimal places.The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 100.Sofia scored 632 on the test.What percent of students scored below Sofia?Round your answer to the nearest hundredth.The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 100.Benita scored 432 on the test.What percent of students scored below Benita?Round your answer to the nearest hundredth.The expression P(z<1.00) represents the area under the standard normal curve below a given value oz. Use your standard normal table to find the indicated area. Use a sketch of the standard normal curve with the appropriate area shaded so this is going to let you find the answer.