| 4x - 8 | < 12
-12 < 4x - 8 < 12......add 8 to every section
-12 + 8 < 4x - 8 + 8 < 12 + 8
-4 < 4x < 20 ....divide every section by 4
-4/4 < 4x/4 < 20/4....simplify
-1 < x < 5 <====
No answer the question is not correct in my point.
<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Answer:
5 s + (3 * 13) + 20 = 7 * 12
Step-by-step explanation: