Line them up
3x3= 9, 3x2= 6, 3x5= 15

Add a 0 under the 9, 7x3= 21, leave the 1 and carry the 2, 7x2= 14+2= 16 leave the 6 and carry the 1, 7x5= 35+1= 36

9+0= 9, 6+1= 7, 5+6= 11 leave 1 carry 1, 1+6= 7+1= 8, 0+3= 3

523
x 73
———
1,569
+ 36,610
———
38,179

4 0

3 years ago

if a right triangle has one side measuring 3√2 and another side measuring 2√3, what is the length of the hypotenuse?

lina2011 [118]

Answer:

Step-by-step explanation:

Given,

Perpendicular ( p ) = 3√2

Base ( b ) = 2√3

Hypotenuse ( h ) = ?

Now, let's find the length of the hypotenuse:

Using Pythagoras theorem:

${h}^{2} = {p}^{2} + {b}^{2}$

plug the values

${h}^{2} = {(3 \sqrt{2} )}^{2} + {(2 \sqrt{3} )}^{2}$

To raise a product to a power, raise each factor to that power

${h}^{2} = 9 \times 2 + 4 \times 3$

Multiply the numbers

${h}^{2} = 18 + 12$

Add the numbers

${h }^{2} = 30$

Take the square root of both sides of the equation

$h = \sqrt{30}$

Hope this helps...

Best regards!!

6 0

4 years ago

Read 2 more answers

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Fofino [41]

Answer:

A is your answer.

Step-by-step explanation:

The quickest way to find this is to count the whole numbers between each point given in the answers and look for the answer that falls between 2 and 3 units.

Answer A, -31/2 and 1 is the only answer that meets this criteria.

4 0

3 years ago