Answer:
WLAN's or Wireless LAN Units have 2 main modes of operation
Explanation:
The Two Main modes of Operation are the following
<u>Infrastructure Mode:</u> in this mode the main WLAN unit becomes the main connection point in which all devices are connected to and the main unit provides an internet connection to all the devices connected to it.
<u>Ad Hoc Mode:</u> in this mode devices transfer data from one another back and forth without permission from a base unit.
Some WLAN units will also include 2 extra modes of operation called Bridge and Wireless Distribution System (WDS).
<u>Bridge Mode:</u> this mode allows the base unit to act as an intermediary and bridge two different connection points. Such as bridging a wired connection with a wireless one.
<u>WDS Mode:</u> this mode uses various access points to wirelessly interconnect devices to the internet using repeaters to transmit connections. It can provide internet to both wired and wireless clients.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
subnet mask
Explanation:
A subnetwork or subnet mask is a logical subdivision of an IP network.
To find out your subnet mask, the simlest way around it is to is to run a simple command line in windows.
Simply press the Windows key and “R” at the same time to open the command prompt and type “cmd” followed by “enter.” This will allow you to see your subnet mask.
In IPv4, the subnet mask 255.255. 255.0 is 32 bits and consists of four 8-bit octets. The address: 10.10. 10.0 subnet mask 255.255.255.0 this simply indicated that the subnet mask consists of a range of IP addresses from 10.10.10.0 - 10.10.10.255.
Subnet masks (IPv4) are often involved in identifying the range of IP addresses that make up a subnet, it can also be described as a group of IP addresses on the same network.
Answer:
B. 1 6 3
Explanation:
Given function definition for calc:
void calc (int a, int& b)
{
int c;
c = a + 2;
a = a * 3;
b = c + a;
}
Function invocation:
x = 1;
y = 2;
z = 3;
calc(x, y);
cout << x << " " << y << " " << z << endl;
- Since x is passed by value, its value remains 1.
- y is passed by reference to the function calc(x,y);
Tracing the function execution:
c=3
a=3
b=c+a = 6;
But b actually corresponds to y. So y=6 after function call.
- Since z is not involved in function call, its value remain 3.
So output: 1 6 3
