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aivan3 [116]
3 years ago
7

If a thread is not finished running, perhaps because it had to wait or it was preempted, it is typically restarted on the same p

rocessor that previously ran it. what is this known as? cooperative multitasking multitasking processor affinity preemptive multitasking
Computers and Technology
1 answer:
andrew11 [14]3 years ago
4 0
<span>If a thread is not finished running, perhaps because it had to wait or it was preempted, it is typically restarted on the same processor that previously ran it.  This is this known as </span>processor affinity. 
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While software vendors generally provide evaluation or demonstration copies of their products, hardware vendors never provide ev
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False

Explanation:

Even with the expenses of hardware, hardware vendor still provide evaluation or demonstration copies of their products just like software vendors but not as often.

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12.2 Sort an array in ascending order Write a program that gets a list of integers from input, and outputs the integers in ascen
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The following code is written in Java, it asks the user for the number of inputs that will be made and then the inputs. These inputs are placed into an array. Then the array is sorted and printed out to the terminal.

public static void sortArrayList() {

           ArrayList<Integer> sortedList = new ArrayList();

           Scanner input = new Scanner(System.in);

           System.out.println("Enter number of digits in Array");

           int numberOfInputs = input.nextInt();

           for (int i = 0; i < numberOfInputs; i++) {

                   System.out.println("Enter a number");

                   sortedList.add(input.nextInt());

           }

           int n = sortedList.size();

           for (int i = 0; i < n; i++)

               for (int j = 0; j < n-i-1; j++)

                   if (sortedList.get(j) > sortedList.get(j + 1))

                   {

                       // swap arr[j+1] and arr[j]

                       int temp = sortedList.get(j);

                       sortedList.set(j, sortedList.get(j + 1));

                       sortedList.set(j + 1, temp);

                   }

           for (int x : sortedList) {

               System.out.println(x);

           }

       }

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