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Below are the choices:
A.
<span>[8 -6] </span>
<span>[-5 4] </span>
<span>B. </span>
<span>[4 -3] </span>
<span>[-2.5 2] </span>
<span>C. </span>
<span>[-4 5] </span>
<span>[6 -8] </span>
<span>D. </span>
<span>[-2 2.5] </span>
<span>[3 -4]
</span>
B because it is the inverse of
<span>(4 6) </span>
<span>(5 8) </span>
<span>Check </span>
<span>(4.0 -3)(4 6) = (1 0) </span>
<span>(-2.5 2)(5 8) = (0 1)</span>
Answer: 2.76 g
Step-by-step explanation:
The formula to find the standard deviation:-
The given data values : 560 g, 562 g, 556 g, 558 g, 560 g, 556 g, 559 g, 561 g, 565 g, 563 g.
Then,
Now,
Then,
Hence, the standard deviation of his measurements = 2.76 g
The answer to your question is 0.046511627906
Explanation:
Simple, use a calculator to answer your question.
If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.
Given 95% confidence level, standard deviation=0.05.
We know that margin of error is the range of values below and above the sample statistic in a confidence interval.
We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data near the mean are more frequent in occurence than data far from mean.
We know that margin of error for a confidence interval is given by:
Me=
α=1-0.95=0.05
α/2=0.025
z with α/2=1.96 (using normal distribution table)
Solving for n using formula of margin of error.
n=
=96.4
By rounding off we will get 97.
Hence the sample size required will be 97.
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The given question is incomplete and the full question is as under:
If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?