Answer:
271,403 is rounded to 270,000 because the 1403 before it is less than 5000, 4 and below drop it down, 5 or more bump it up.
Step-by-step explanation:
Answer:
a = (p - 3b)/10
Step-by-step explanation:
Isolate the variable, a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS (Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction).
p = 10a + 3b
First, subtract 3b from both sides.
p (-3b) = 10a + 3b (-3b)
p - 3b = 10a
Next, isolate the a. Divide 10 from both sides.
(p - 3b)/10 = (10a)/10
(p - 3b)/10 = a
a = (p - 3b)/10 is your answer.
~
Answer:
6,000 toothpicks
Step-by-step explanation:
In this question, we are trying to evaluate the number of toothpicks a company must sell to ensure that the money spent on production is exactly equal to revenue from sales.
What we do is this!
Let’s assign a variable to represent the number of tooth picks sold and produced by the company. Let us call this number x.
First, we evaluate the total amount spent on production of x toothpicks. From the question, we can see that the cost of producing a single toothpick is $0.01, hence, to produce x toothpicks, amount spent asides the fixed cost is $0.01 * x = $0.01x
Now, the total cost on production which includes the fixed cost of the company would be $(0.01x + 60). This is the total amount spent to produce the goods.
Now revenue from sales for x toothpicks at $0.02 each is $0.02x
Since we are looking to Breakeven, we equate the costs to the revenue.
0.01x + 60 = 0.02x
0.02x-0.01x = 60
0.01x = 60
x = 60/0.01 = 6,000 toothpicks
Do you mean
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
remember that
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
resolve the
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first
![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)
so
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or
![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean
