5000, take 3500 multiplied by 2/7 to find the amount of money deposited per month which is 1000 then multiply it by 5 to find the deposit over 5 months
Well if 12 and 36 is a fraction then it would most likely be 1/3 , I asked my teacher and this is what she said.
-35 = h
To get rid of fractions you simply multiply the denominator to the whole equation. -7 =h/5 can be -7(5) = (h/5)(5)
Even without doing the math, (and without having the requisite diagram to view), it seems likely that the rectangle was simply divided along the diagonal. And, if that's the case then the two triangles formed would have the same area. So, if one triangle's area ABC is 600 sq. yds. as the problem states, then the other triangle ACD also would be 600 sq. yds.
But if we do the math anyway, we can get the same result.
Keep in mind that:
P of rectangle = 2 ( l + w)
A of rectangle = (l x w)
A of triangle = h x b divided by 2
I'd say that the length of the rectangle is 40 and the width is 30.
P of rectangle is 2 (30 + 40) = 140 .... check
A of rectangle is 30 x 40 = 1,200 .... check
A of triangle is 30 x 40 divided by 2 = 600 ...... check
Answer:
-10
-5
5
Step-by-step explanation:
From the answers given, you probably mean f(x) = x^3 + 10x2 – 25x – 250
The Remainder Theorem is going to take a bit to solve.
You have to try the factors of 250. One way to make your life a lot easier is to graph the equation. That will give you the roots.
The graph appears below. Since the y intercept is -250 the graph goes down quite a bit and if you show the y intercept then it will not be easy to see the roots.
However just to get the roots, the graph shows that
x = -10
x = - 5
x = 5
The last answer is the right one. To use the remainder theorem, you could show none of the answers will give 0s except the last one. For example, the second one will give
f((10) = 10^3 + 10*10^2 - 25*10 - 250
f(10) = 1000 + 1000 - 250 - 250
f(10) = 2000 - 500
f(10) = 1500 which is not 0.
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f(1) = (1)^3 + 10*(1)^2 - 25(1) - 250
f(1) = 1 + 10 - 25 - 250
f(1) = -264 which again is not zero