The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250
At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5
So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
</span>
S = 10*m^(2/3)
S = 10*(450000)^(2/3)
S = 58,723.014617533
S = 58,723
<h3>Answer: Approximately 58,723 square cm.</h3>
65+50x = 55x + 20
-50x -50
65=5x+20
- 20 - 20
55=5x
55/5= 5x/5
11=x
The solution represents that it 11 months will make both gyms the exact same price.
Answer:
please rewrite the function. the latex function did not work.
Answer:
4.5
Step-by-step explanation:
