Given problem;
A = 
r²
Solve for π;
To solve for π implies that we make it the subject of the expression.
So;
A = π r²
Now multiply both sides by 
So;
A x = x r² x
r² cancels out from the right side and leaves only π;
π = 
So 
Answer:
h(4) = –12
Step-by-step explanation:
⇒ What the question is asking is that when the function h(n) = –2n(2) + 4 is h(4), what will the function repond to when solving for h(4)? So, solve for the function h(4):
h(4) = –2n(2) + 4
⇒ Since n was replaced with 4 in the function h(4), substitute any n for 4 into the function:
h(4) = –2(4)(2) + 4
⇒ Simplify:
h(4) = –16 + 4
⇒ Solve:
h(4) = –12
<u>Answer:</u> h(4) = –12
<em>I hope you understand and that this helps with your question! </em>:)
Answer:
solution is x=3
Step-by-step explanation:
apply log property
log a- log b= log a/b
we have log on both sides
so we remove the log and make the arguments equal
solve for x, multiply whole equation by 3
now plug in 3 for x and check
solution is x=3
Answer:
A. 5.3
Step-by-step explanation:
While both of these numbers are close to 7, 5.3 is the closest and we can find this out with subtraction. So, 9.9 - 7 = 2.9, but 7 - 5.3 = 1.7. Which one can we determine is closer? Well, 2.9 > 1.7, so our answer must be A. 5.3!
Have a nice day and I hope this helped!
A rug maker is using a pattern that is a rectangle with a length of 96 inches and a width of 60 inches. The rug maker wants to increase each dimension by a different amount. Let l and w be the increases in the length and width. Write and simplify an expression for the perimeter of the new pattern.
p=2(96+l)+2(60+w)
This is the equation. p is for perimeter. (96+l) represents the original length plus the change in length. The 2 before (96+l) represents that there is one length on each side of the rectangle.
Same for the width. (60+w) represents the original width plus the change in width. The 2 before (60+w) represents that there is one width on each side of the rectangle.
The simplified equation is p=(192+2l)+(120+2w) (this is your answer)
I hope this helps!
