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agasfer [191]
3 years ago
15

Is this a function? A) YesB) No

Mathematics
2 answers:
liq [111]3 years ago
7 0
I think it is not sure thou
Rzqust [24]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

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What is the domain of the function
Anon25 [30]
The answer is -2,2,3,4
7 0
3 years ago
The diameter of a circle X is 18 cm the diameter of circle Y is 31 cm which circle has the greater area and by how much you 3.14
Finger [1]
Area of a circle = (pi)(radius squared)
A of Circle X= (3.14)(18cm/2)squared

We need to divide the diameter in half to get the radius.
A of Circle X= (3.14)(9) squared
A of Circle X= (3.14)(81)
A if Circle X= 254.34 cm


A of Circle Y= (3.14)(31cm/2)squared

We need to divide the diameter in half to get the radius.
A of Circle Y= (3.14)(15.5) squared
A of Circle Y= (3.14)(240.25)
A if Circle Y= 754.39 cm

Find the difference in Area:
=Circle Y - Circle X
=754.39 - 254.34
=500.05 cm difference

Circle Y has the greater area of 754.39. It it greater than Circle X by 500.05 cm
7 0
4 years ago
Please help me fast :) I'll give brainly and you'll get 15 points
Alekssandra [29.7K]

Answer:

Rational

Step-by-step explanation:

8 0
3 years ago
Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
4 years ago
The trapezoids are similar. The area of the smaller trapezoid is 709 m2. Find the area of the larger trapezoid to the nearest wh
mars1129 [50]

Answer:

564 (57/24)2

= 564 · 5.64

= 3,181

Step-by-step explanation:

i think i dont know

6 0
3 years ago
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