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Anna71 [15]
3 years ago
11

15 Points please help me fast i need help please help me

Mathematics
1 answer:
Flura [38]3 years ago
8 0

Answer:

Look at the image.

Step-by-step explanation:

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Simplify the following exponential expression. Show your work step by step and list the Properties of Exponents used to solve th
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3x^0 (2x^3y^2)^4

--------------------------

(4x^7y^4) ^2


= 3 * 1  (2x^3y^2)^4

--------------------------      Zero Exponent Property  X^0 =1

(4x^7y^4) ^2


3   (2^4 *x^3*4 y^2*4)

--------------------------     power of a power property  x^a ^b = x^(a*b)

4^2 x^7*2 y^4*2

3   *16 *x^12 y^8

--------------------------     simplify

16 x^14 y^8

3    *x^12 y^8

--------------------------     simplify

x^14 y^8

3    *x^(12-14) y^(8-8)

--------------------------     Quotient of Power  X^a/ X^b = X^ (a-b)


3x^-2 y^0  simplify

3x^-2 *1      Zero Exponent Property  X^0 =1

3 / x^2   Negative exponent property  x^-a = 1/x^a

5 0
3 years ago
Last year, Mary's vegetable garden was a rectangle that measured 6 ft by 8 ft.
Bess [88]

Answer:

12 ft

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
3. Which ordered pair is a solution of the equation y=x-3?
Vlada [557]
The answer is B (-5,2)
3 0
3 years ago
% is the correct percentage conversion for 2/5
denis-greek [22]

Answer:

%40

Step-by-step explanation:

<u>Step 1:  Divide 2/5</u>

2/5 = 0.4

<u>Step 2:  Convert to Decimal by multiplying by 100</u>

0.4 * 100 = %40

Answer:  %40

6 0
3 years ago
Read 2 more answers
One number is eight more than a second number. Five times the first is 8 less than 2 times the second. Find the numbers.
Elena-2011 [213]

Step-by-step explanation:

let the 2 numbers be x and y.

x - 8 = y --(1)

5x = 2y - 8 --(2)

sub (1) into (2):

5x = 2(x - 8) - 8

5x = 2x - 24

3x = -24

x = -8

sub x = -8 into (1):

y = -8 - 8 = -16

first number is -8 and second number is -16.

Topic: algebraic equations + simultaneous equation

If you like to venture further, feel free to check out my insta (learntionary). I'll be constantly posting math tips and notes! Thanks!

4 0
3 years ago
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