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3 years ago

I need help on this question, I really do not know this.

Mathematics

1 answer:

marissa [1.9K]3 years ago

3 0

Answer: A

Pie charts are generally used to show percentages or proportional data.

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2 less than the product of 9 and a number is 4 what is the equation

Gnesinka [82]

Answer:

Step-by-step explanation:

2 less then the product of 9 and a number is 4

" the product " is the result of multiplication

the product of 9 and a number...9x

2 less......-2

is 4...= 4

9x - 2 = 4 <===

4 0

3 years ago

The length of a rectangle is 8.more than the width. the area is 84 square feet. find the length and width of the rectangle.

Anton [14]

I have three ways how much is it now and I will be ready to answering your question

5 0

3 years ago

Three salesmen work for the same company, selling the same product. And, although they are all paid on a weekly basis, each sale

LenaWriter [7]

Based on the amount that both Salesmen A and B earn per sale, the number of sales they both had was 12 sales.

<h3>How many sales did Salesmen A and B have?</h3>

Sales commission is a key aspect of sales compensation. It's the amount of money a salesperson earns based on the number of sales they have been able to make.

We are told that;

Salesman A gets $65 per sale.

Salesman B gets $300 and $40 per sale.

Assuming the number of sales to take them both to the same amount is x, the relevant formulas would be:

65x = 300 + 40x

Rearranging gives;

65x - 40x = 300

25x = 300

x = 300/25

x = 12 sales

The amount that salesman A earned is = 65 * 12 = $780

The amount that salesman B earned is = 300 + (40 * 12) = $780

Read more about Commission based sales at; brainly.com/question/24951536

#SPJ1

4 0

2 years ago

Sin(A+B) sin(A-B) /sin^A Cos^B=1-cot^A Tan^B

telo118 [61]

In order to prove

$\dfrac{\sin(x+y)\sin(x-y)}{\sin^2(x)\cos^2(x)}=1-\cot^2(x)\tan^2(y)$

Let's write both sides in terms of $\sin(x),\ \sin^2(x),\ \cos(x),\ \cos^2(x)$ only.

Let's start with the left hand side: we can use the formula for sum and subtraction of the sine to write

$\sin(x+y)=\cos(y)\sin(x)+\cos(x)\sin(y)$

and

$\sin(x-y)=\cos(y)\sin(x)-\cos(x)\sin(y)$

So, their multiplication is

$\sin(x+y)\sin(x-y)=(\cos(y)\sin(x))^2-(\cos(x)\sin(y))^2\\=\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)$

So, the left hand side simplifies to

$\dfrac{\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

Now, on with the right hand side. We have

$1-\cot^2(x)\tan^2(y)=1-\dfrac{\cos^2(x)}{\sin^2(x)}\cdot\dfrac{\sin^2(y)}{\cos^2(y)} = 1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

Now simply make this expression one fraction:

$1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}=\dfrac{\sin^2(x)\cos^2(y)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

And as you can see, the two sides are equal.

6 0

4 years ago

True or false: a mosaic plot is useful for visualizing the relationship between a numerical and a categorical variable.

Ivahew [28]

It is false that for visualizing the relationship between a numerical and a categorical variable, a mosaic plot is useful. This is because the best plot to use for this kind of relationship is the side by side box plot.

Comparing the distribution of a numerical variable across the levels of a categorical variable is something we usually consider in this type of relationship.

The levels of one categorical variable by means of a quantitative variable is best compared by using the visual display called the side by side boxplot. <span>By placing single boxplots adjacent to one another on a single scale, the side by side box plot is constructed.</span>

3 0

4 years ago