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2 years ago

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%3A%20value%20%5C%3A%20of%20%5C%3A%20x" id="TexFormula1" title=" 5{x}^{2} + 2x = 7x + 3x \\ find \: the \: value \: of \: x" alt=" 5{x}^{2} + 2x = 7x + 3x \\ find \: the \: value \: of \: x" align="absmiddle" class="latex-formula">
please no irrelevant answers

1 answer:

lana [24]2 years ago

4 0

Answer:

$5 {x}^{2} + 2x = 7x + 3x \\ 5 {x}^{2} + 2x = 10x \\ 5 {x}^{2} = 10x - 2x \\ 5 {x}^{2} = 8x \\ 5x = 8 \\ x = \frac{8}{5} = 1.6 \\ thank \: you$

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A) 101* (x+12) <br> B)63* (7x-14) <br> C)(2x+3) (x+41)* <br> Please help :)

IceJOKER [234]

Answer:

A. x+12 = 101

-12 -12

x=89

B. 7x-14 = 63

+14 +14

7x=77

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2 years ago

A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of t

Tomtit [17]

Answer:

$0.54\,\,m^3$

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × $\frac{1.2}{2}=0.6\,\,m$ (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= $0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6$

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