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Vesnalui [34]
3 years ago
9

Need help anyone can help giving brain liest

Mathematics
2 answers:
trapecia [35]3 years ago
6 0

Answer:

14 gel pens/minute

Step-by-step explanation:

divide the amount by time.

210/15 = 14

Vladimir [108]3 years ago
3 0

Answer:

14

Step-by-step explanation:

You might be interested in
Please help immediately ​
Burka [1]

Answer:    f'(1)=\dfrac{4}{2y+1}

<u>Step-by-step explanation:</u>

To find the tangent, you need to find the derivative with respect to x.

Then substitute x = 1 into the derivative.

Given:         0 = 2x² - xy - y²

Derivative:  0 = 4x - y' - 2yy'

Solve for y': 2yy' + y' = 4x

                   y'(2y + 1) = 4x

                   y'=\dfrac{4x}{2y+1}

\text{Substitute x = 1:}\quad y'(1)=\dfrac{4}{2y+1}

8 0
3 years ago
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
2 years ago
Can somebody please help me with this problem please
Furkat [3]

Answer:

m = 3, n = 4

Step-by-step explanation:

Solve using the substitution process. First, start with the second equation:

2m + 2n = 14

Simplify. Divide 2 from all terms within the equation. What you do to one side, you do to the other:

(2m + 2n)/2 = (14)/2

m + n = 7

Isolate the variable m. Subtract n from both sides:

m + n (-n) = 7 (-n)

m = 7 - n

Plug in 7 - n for m in the first equation:

-5m + 9n = 21

-5(7 - n) + 9n = 21

Solve. First, distribute -5 to all terms within the parenthesis:

(-35 + 5n) + 9n = 21

Simplify. Combine like terms:

-35 + (5n + 9n) = 21

-35 + 14n = 21

Isolate the variable, n. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, add 35 to both sides:

14n - 35 (+35) = 21 (+35)

14n = 21 + 35

14n = 56

Isolate the variable n. Divide 14 from both sides:

(14n)/14 = (56)/14

n = 56/14

n = 4

Plug in 4 to n in one of the equations, and solve for m.

2m + 2n = 14

2m + 2(4) = 14

2m + 8 = 14

Isolate the variable, m. Do the opposite of PEMDAS. First, subtract 8 from both sides:

2m + 8 (-8) = 14 (-8)

2m = 14 - 8

2m = 6

Divide 2 from both sides:

(2m)/2 = (6)/2

m = 6/2

m = 3

Your answers: m = 3, n = 4

~

6 0
3 years ago
Read 2 more answers
G(x)=− 4 x 2 ​ +7g, left parenthesis, x, right parenthesis, equals, minus, start fraction, x, start superscript, 2, end superscr
steposvetlana [31]
For this case, what we should do is evaluate the function for different points within the range shown.
 We then have the following table:
 x      g(x) 
 -2    -9
 -1     3
  0     7
  1     3
  2    -9
  3    -29
  4    -57
 From where we observed that the average rate of change is:
 -13
 Answer:
 
the average rate of change of g over the interval [-2,4] is:
 
-13
4 0
3 years ago
A sphere of radius 3 is inscribed in a cylinder. What is the volume inside the cylinder but not inside the sphere?
Fed [463]

Answer:

18pi units³ or 56.5 units³ (3 sf)

Step-by-step explanation:

pi×r²×h - (4/3)(pi×r³)

r = 3 h = 2r = 6

pi(3²×6 - (4/3)(3³))

18pi units³

8 0
3 years ago
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