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Pani-rosa [81]
3 years ago
5

5х + 34 = -2 (1 - 7x) help me solve it step by step !

Mathematics
1 answer:
nataly862011 [7]3 years ago
6 0

5x+34=-2(1-7x)

Steps:

5x+34=-2+14x
5x+34-14x= -2
-9x + 34= -2
-9x = -2-34
-9x = -36
X= -36/-9


Answer: x= 4

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X(x-1)(x^2+4)=(x^2-x)(x^2+4)=(x^4)+(4x^2)-(x^3)-(4x)=(x^4)-x(x^2+4)+(4x^2)
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3 years ago
Place the expressions that are equivalent under the corresponding expression in the table.
serg [7]

Answer:

Step-by-step explanation:20

20  130  3  8.12 - 1) 2:2  12-1  21=-11 # 1 - 2 1212 II + 3) 472 I + 3 2(1 - 1) -1 2:2 3(12 - 1) 32 – 23– 3+.

5 0
2 years ago
Read 2 more answers
1. (3x + 7) + (8x + 2)
Mashutka [201]
11x+9


Step by step:
Remove the parenthesis
3x+7+8x+2
Collect like terms
11x+7+2
Add 7+2
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5 0
3 years ago
If f(x) = 4x²-2 then f(-2) is​
klemol [59]
To find f(-2), substitute (-2) into x of the function f(x) = 4x^2-2
We get, f(-2) = 4(-2)^2 - 2
= (4*4)-2 = 16-2 = 14
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3 0
2 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
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