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Pani-rosa [81]
3 years ago
5

5х + 34 = -2 (1 - 7x) help me solve it step by step !

Mathematics
1 answer:
nataly862011 [7]3 years ago
6 0

5x+34=-2(1-7x)

Steps:

5x+34=-2+14x
5x+34-14x= -2
-9x + 34= -2
-9x = -2-34
-9x = -36
X= -36/-9


Answer: x= 4

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HELP What is the area of a circle with a radius of 13 feet? IT IS NOT 530.93 ft ​
NeTakaya

Answer:

530.66

Step-by-step explanation:

to find the area you need to do pi times the radius square and to find the radius squared you just times it by its self so 13 times 13 which is 169 and pi is 3.14

so now you just do 3.14x169=530.66

8 0
3 years ago
In ΔVWX, the measure of ∠X=90°, XW = 65, WV = 97, and VX = 72. What is the value of the cosine of ∠V to the nearest hundredth?
bonufazy [111]

Answer:

The cosine of ∠V is of 0.74.

Step-by-step explanation:

Relations in a right triangle:

The cosine of an angle is given by the length of the adjacent side divided by the length of the hypotenuse.

XW = 65, WV = 97, and VX = 72.

\sqrt{65^2+72^2} = 97, and thus, this is a right triangle.

What is the value of the cosine of ∠V to the nearest hundredth?

The hypotenuse is the largest side, that is, WV = 97.

The adjacent side of angle V is VX = 72. So

\cos{B} = \frac{72}{97} = 0.74

The cosine of ∠V is of 0.74.

8 0
3 years ago
According to postal regulations, a carton is classified as "oversized" if the sum of its height and girth (the perimeter of its
Amanda [17]

Answer:

V(max) =  8712.07 in³

Dimensions:

x (side of the square base)  = 16.33 in

girth   = 65.32 in

height = 32.67 in

Step-by-step explanation:

Let

x  = side of the square base

h = the height of the postal

Then according to problem statement we have:

girth = 4*x     (perimeter of the base)

and

4* x  +  h  = 98  (at the most)   so   h = 98 - 4x  (1)

Then

V = x²*h

V = x²* ( 98 - 4x)

V(x) = 98*x² - 4x³

Taking dervatives (both menbers of the equation we have:

V´(x)  =  196 x   -  12 x²        ⇒   V´(x) = 0

196x - 12x²  = 0   first root of the equation  x = 0

Then   196 -12x = 0      12x = 196     x = 196/12

x = 16,33 in      ⇒    girth = 4 * (16.33)       ⇒ girth = 65.32 in

and from equation (1)

y = 98 - 4x       ⇒  y = 98 -4 (16,33)

y = 32.67 in

and maximun volume of a carton V is

V(max) = (16,33)²* 32,67

V(max) = 8712.07 in³

3 0
3 years ago
Help me please. 30 points :)
Nataly [62]

\frac{(5 \:  -  \: 8x)}{( \sqrt{5 \:  -  \: 8x} )}  \:  =  \:  \sqrt{5 \:  -  \: 8x}
For the result to be Real,
5 \:  -  \: 8x \:  \geqslant  \: 0
8x \:  \leqslant  \: 5
x \:  \leqslant  \:  \frac{5}{8}
( \frac{(5 - 8x)}{( \sqrt{5 - 8x} )} ) \:  \times  \:  (\frac{ \sqrt{5 - 8x} }{ \sqrt{5 - 8x} } ) \:  =  \:  \frac{ {(5 \:  -  \: 8x)}^{ \frac{3}{2} } }{(5 \:  -  \: 8x)}
Hence,
\frac{{(5 \:  -  \: 8x)}^{ \frac{3}{2} } }{(5 \:  -  \: 8x)}
is the required form.

3 0
3 years ago
you are shopping for disposable cameras to hand out at a party. the daytime cameras costs 2.75 dollars and the flash camera cost
LenKa [72]

The solutions that involve whole numbers of cameras are (7, 13), (8, 12), (9, 11), (10, 10), (11, 9), (12, 8) and (13, 7)

<h3>Write and solve a compound inequality for this solution. </h3>

The given parameters are:

  • Daytime cameras = $2.75
  • Flash camera = $4.25
  • Number of cameras = 20 cameras
  • Amount spent = Between $65 and $75

Represent the daytime camera with x and the flash camera with y.

So, we have:

x + y = 20

65 <=2.75x + 4.25y <= 75

Make y the subject in x + y = 20

y = 20 - x

Substitute y = 20 - x in 65 <=2.75x + 4.25y <= 75

65 <=2.75x + 4.25(20 - x) <= 75

Expand

65 <=2.75x + 85 - 4.25x <= 75

This gives

65 <=-1.5x+ 85  <= 75

Subtract 85 from the inequality

-20 <=-1.5x <= -10

Split the inequality

-1.5x >= -20 and -1.5x <= -10

Divide by -1.5

x <= 13.33 and x >= 6.67

Combine the inequality

6.67 <= x <= 13.33

<h3>List all of the solutions that involve whole numbers of cameras.</h3>

In (a), we have:

6.67 <= x <= 13.33

This means that:

x = 7, 8, 9, 10, 11, 12, 13

Recall that:

y = 20 - x

So, we have:

y = 13, 12, 11, 10, 9, 8, 7

So, the solutions that involve whole numbers of cameras are (7, 13), (8, 12), (9, 11), (10, 10), (11, 9), (12, 8) and (13, 7)

Read more about inequality at:

brainly.com/question/25275758

#SPJ1

4 0
2 years ago
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