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4 years ago

5

5х + 34 = -2 (1 - 7x) help me solve it step by step !

1 answer:

nataly862011 [7]4 years ago

6 0

5x+34=-2(1-7x)

Steps:

5x+34=-2+14x
5x+34-14x= -2
-9x + 34= -2
-9x = -2-34
-9x = -36
X= -36/-9

Answer: x= 4

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2/3x(-3)+(-2)-1/3x hurry i need this answered

mrs_skeptik [129]

Answer:

-7x/3 - 2

Step-by-step explanation:

7 0

3 years ago

2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

3 years ago

Kai calculates that he spends 75 minutes of a school day in science class. if he spends 500 minutes in school, what percent of h

Ne4ueva [31]

(75/500) x 100
=(3/20) x100
=15%

5 0

3 years ago

Write the single expression in index form 2²×2⁴×2³

Svetlanka [38]

Answer:

Just break down the answer.

Step-by-step explanation

(2•2)•(2•2•2•2)•(2•2•2)

You are just see how much you have in each exponent. The number you have in exponents is main number you put out.

7 0

3 years ago

Read 2 more answers

The reaction of the body to a dose of medicine can sometimes be represented by an equation of the formR = M^2 (C/2- M/3),where C

mr Goodwill [35]

Answer:

The derivative is $\frac{dR}{dM} = CM - M^2$

Step-by-step explanation:

From the question we are told that

The equation representing the reaction is $R = M^2 (\frac{C}{2} - \frac{M}{3} )$

Generally this equation can be represented as

$R = \frac{C M^2}{2} - \frac{M^3}{3}$

Generally $\frac{dR}{dM}$ as a function of M is mathematically represented as

$\frac{dR}{dM} = 2 * \frac{C M^{2 - 1 }}{2} + 3 * \frac{M^{3-1}}{3}$

=> $\frac{dR}{dM} = CM - M^2$

8 0

4 years ago