Using the concept of domain, the domain of (f.g)(x) is given by:
{x ∈ ℝ | x ≠ 3}
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- The domain of a function is given by all possible input values, that is, <u>on a graph, all values that the x-axis assumes.</u>
- In the graph, <u>function f assumes all real values.</u>
- Function g is not defined for x = 3, thus, it's domain is all real values except 3.
- Thus, the multiplication, as
, will also not be defined at x = 3, and the domain of the multiplication is:
{x ∈ ℝ | x ≠ 3}
A similar problem is given at brainly.com/question/4175434
Answer:
Given
x+y+z=0
⟹x+y=−z
Cubing on both sides
(x+y) 3 =(−z) 3
⟹x 3 +y 3 +3x 2y+3xy 2 =−z 3
⟹x 3 +y 3 +3xy(x+y)=−z 3
⟹x 3+y 3+3xy(−z)=−z 3
⟹x 3 +y 3−3xyz=−z 3
⟹x 3 +y 3 +z 3 =3xyz
Step-by-step explanation:
Hope it is helpful.....
A points location will change after you add a negative value to the y coordinate even if you leave the x coordinate the name because you are changing the value of the y coordinate. For example, if you have (4,6) as a coordinate and then change it to (4,-6), the coordinate will now just be on the other side of the x axis
Hey there!
The answer to your question is 
Given:

First, we distribute the negative sign to both terms (
) This would make the
negative and the
positive, so we have:

Add them together and we get:

Have a nice day!