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Over [174]
3 years ago
10

16 Which equations represent a relationship where у

Mathematics
1 answer:
Effectus [21]3 years ago
8 0

Answer:

b

Step-by-step explanation:

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the acceleration of an object due to gravity is 32 feet per second squared . what is the acceleratiin due to gravity in inches p
Hitman42 [59]
1 foot = 12 inches
32 · 12 = 384 in/ s²
Answer: A ) 384 inches per second squared
Hope this helps you !!
3 0
3 years ago
Read 2 more answers
Would each of them be able to be the side lengths of a triangle?
ratelena [41]
Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²

First posible triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=5                  (5²=25)

13³=144 + 25


Answer:can be side lengths of a triangle

Second triangle:
 hypotenuse=12.6    (12.6²=158.76)
leg₁=6.7                ( 6.7²=44.89)
leg₂=6.5                  (6.5²=42.25)

leg₁²+leg₂²=44.89+42.25=87.14≠158.76

Answer: cannot be side lenghts of a triangle.

third triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=11                  (11²=121)

leg₁²+leg₂²=144+121=265≠169

Answer: cannot be side lenghts of a triangle.

fourth triangle:
hypotenuse=13   (13²=169)
leg₁=6                ( 6²=36)
leg₂=4                  (4²=16)

leg₁²+leg₁²=36+16=52≠169

Answer: cannot be side lenghts of a triangle.
8 0
3 years ago
Read 2 more answers
HELP PLEASE!!! I need help with this question!
AlexFokin [52]

Answer:

\large\boxed{PS=10\sqrt5}

Step-by-step explanation:

ΔPQS, ΔRQP and ΔRPS are similar (AA). Therefore the sides are in proportion:

\dfrac{QR}{RP}=\dfrac{RP}{RS}

We have:

QR=5,\ RS=20

Substitute:

\dfrac{5}{RP}=\dfrc{RP}{20}                <em>cross multiply</em>

RP^2=(5)(20)\\\\RP^2=100\to RP=\sqrt{100}\\\\RP=10

Use the Pythagorean theorem:

PS^2=PR^2+RS^2

Substitute:

PS^2=10^2+20^2\\\\PS^2=100+400\\\\PS^2=500\to PS=\sqrt{500}\\\\PS=\sqrt{100\cdot5}\\\\PS=\sqrt{100}\cdot\sqrt5\\\\PS=10\sqrt5

6 0
3 years ago
What horsepower is required to lift an 8,000 pound aircraft six feet in two minutes?
Dafna11 [192]

Answer:

The horsepower required is 235440 watt.

Step-by-step explanation:

To find : What horsepower is required to lift an 8,000 pound aircraft six feet in two minutes?

Solution :

The horsepower formula is given by,

W=\frac{mgh}{t}

Where, W is the horsepower

m is the mass m=8000 pound

g is the gravitational constant g=9.81

t is the time t= 2 minutes

h is the height h=6 feet

Substitute all values in the formula,

W=\frac{8000\times 9.81\times 6}{2}

W=\frac{470880}{2}

W=235440

Therefore, The horsepower required is 235440 watt.

6 0
3 years ago
Simplify rational equations <br><br><br><br> y=x^2+3x/x<br><br>Show work, please
lora16 [44]

Answer:

6

Step-by-step explanation:

2y x 3x

7 0
4 years ago
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