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3 years ago

PLEASE HELPPPPPPPPP!!!!?!?! ASAP WILL GIVE BRAINLIEST IF CORRECT PLSSS AND THANK YOU.

Mathematics

1 answer:

Assoli18 [71]3 years ago

8 0

Answer:

square root of 14

Step-by-step explanation:

square root of 7 to the square is 7

7+7 = 14

square root of 14 can't be simpliflied

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8-4x=4-3(2x+6) ??? Someone help

Maurinko [17]

8 - 4x=4 - 3(2x+6)
<=> 8 - 4x = 4 - 6x - 18
<=> 8 - 4 + 18 = 4x - 6x
<=> 22 = -2x
x = -11

7 0

3 years ago

Read 2 more answers

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

3 years ago

Need answer ASAP!! Find the area of the shaded region.

qwelly [4]

Answer:

(5x² +7x -26) units²

Step-by-step explanation:

$\boxed{area \: of \: rectangle = length \times breadth}$

Area of shaded region

= Area of larger rectangle -area of smaller rectangle

Area of larger rectangle

= (3x -4)(2x +2)

= 3x(2x) +3x(2) -4(2x) -4(2) (Expand)

= 6x² +6x -8x -8

= 6x² -2x -8

Area of smaller rectangle

= (x -6)(x -3)

= x² -3x -6x +18 (Expand)

= x² -9x +18

Area of shaded region

= 6x² -2x -8 -(x² -9x +18)

= 6x² -2x -8 -x² +9x -18

= 5x² +7x -26

4 0

3 years ago

Find z1z2 if z1 = 2/5(cos63° + isin63°) and z2 = 10/3(cos117° + isin117°).

Airida [17]

Answer:

-10/3 is the answer

Step-by-step explanation:

Given are two complex numbers as

$z1=\frac{2}{5} (cos63 + isin63)\\z2=\frac{10}{3} (cos 117 + isin117})$

Recall Demoivre theorem as

(cosA+isinA)(cos A+isin B) = cos(A+B)+isin(A+B)

Hence here we have sum of angles as

A+B = 63+117 =180

$z1z2=\frac{2}{5} \frac{10}{3} (cos180+isin180)$

= $\frac{-10}{3}$

Since sin180=0 and cos 180=-1

7 0

3 years ago

Can someone help me with this? I don't really understand it

SSSSS [86.1K]

Answer:

#1 goes to B.

#2 goes to C.

#3 goes to D.

#4 goes to A.

Hope this helps.

6 0

3 years ago