Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
Answer:
x+2y=0
Step-by-step explanation:
y-y1=m(x-x1)
y-(-2)=-1/2(x-4)
y+2=-1/2x+4/2
y+2=-1/2x+2
y-(-1/2x)=2-2
y+1/2x=0
1/2x+y=0
2(1/2x+y)=2(0)
x+2y=0
Answer:
( C ) ΔMLN ≅ΔTSR
Step-by-step explanation:
Okay I got you!
So if the triangle <u>str</u> was flipped and rotated the other way then you will see that they are similar. They are asking what other "pairs" could you do to make it equivalent. Since M = T then you got your first pair. Next you go to N and when you look at the shape you'll see it will be S. N=S. And the last one would be L=R. I hope I was helpful enough! uwu Try to draw them out it will be helpful!!
Answer:
51
Step-by-step explanation:
Hope this helps. . .