Answer:
1) f(g(0)) = 0
2) g(f(2)) = 2
3) g(g(0)) = 8
Step-by-step explanation:
Here, the given functions are:
g(x) = 3 x +2 and f(x)= (x-2)/3
1. Now, f(g(x)) = f(3x+2)
Also, f(3x+2) = (3x+2 -2) /3 = x
So, f(g(x)) = x
⇒ f(g(0)) = 0
2. g(f(x)) = g((x-2)/3) = 3((x-2)/3) +2
or, g(f(x)) = x
⇒ g(f(2)) = 3((2)-2/3) +2 = 2
or, g(f(2)) = 2
3. g(g(0)= g( 3 (0) +2) = g(2)
Now, g(2) = 3(2) + 2 = 6 + 2 = 8
or, g(g(0)) = 8
Answer:
Therefore the answer is 20.
Step-by-step explanation:
We know that
class interval = range / number of classes
But here number of classes is not given , so we use the formula
class interval = range / ( 1+ 3.322 log N)
where , range =maximum - minimum = 220-100 = 120
N= number of observations = 50
class interval = 120 / ( 1+ 3.322 * log 50) = 18.06
Rounding up to a convinient number
Thus , class intervai = 20
Therefore the answer is 20.
Could you give me just one equation if you could?
Answer:
range of scores on final exam student get B is 90 to 100
Step-by-step explanation:
given data
Psychology 101 score = 66
average of his midterm = between 78 and 90
maximum = 100 points
to find out
range of scores on final exam student get B
solution
we consider here lowest marks need in final = x
so average at two marks should be
equation is
average marks = 0.5 × ( mid term marks + final marks ) .................1
put here value
78 = 0.5 × ( 66 + x )
x = 90
and
90 = 0.5 × ( 66 + x )
x = 114
so range 90 to 114
but maximum marks is 100 so
range of scores on final exam student get B is 90 to 100
