Answer:
Step-by-step explanation:
Theorm-The Fundamental Theorem of Algebra: If P(x) is a polynomial of degree n ≥ 1, then P(x) = 0 has exactly n roots, including multiple and complex roots.
Let's verify that the Fundamental Theorem of Algebra holds for quadratic polynomials.
A quadratic polynomial is a second degree polynomial. According to the Fundamental Theorem of Algebra, the quadratic set = 0 has exactly two roots.
As we have seen, factoring a quadratic equation will result in one of three possible situations.
graph 1
The quadratic may have 2 distinct real roots. This graph crosses the
x-axis in two locations. These graphs may open upward or downward.
graph 2
It may appear that the quadratic has only one real root. But, it actually has one repeated root. This graph is tangent to the x-axis in one location (touching once).
graph 3
The quadratic may have two non-real complex roots called a conjugate pair. This graph will not cross or touch the x-axis, but it will have two roots.
Find the common ratio by dividing.
16 / 8 = 2
8 / a = 2
2 / b = 2
The common ratio is 2.
Since we need to find the values of a and b, use the common ratio to solve for them.
8 / 2 = 4 (a)
2 / 2 = 1 (b)
Now, we know that first 5 terms.
We can solve for the 8th term using the previous terms and the common ratio.
6th term: 1 / 2 = 0.5
7th term: 0.5 / 2 = 0.25
8th term: 0.25 / 2 = 0.125
Part A: 2
Part B: a = 4, b = 1
Part C: 0.125
Best of Luck!
Answer:
Vertical Pair
Step-by-step explanation:
...............It's Vertical..........
Answer:
Step-by-step explanation:
2(l+b)=16
Also it is given that l=2b+2
2(2b+2+b)=16
3b+2=8
b=2metre
l=2(2)+2
l=6metre
Answer:
B. Alternate interior angles
Step-by-step explanation:
<4 and <5 are inside the parallel lines on alternate sides of the third line.
