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3 years ago

What is the relationship between the 3's in the number 9,338?

Mathematics

2 answers:

Serhud [2]3 years ago

4 0

The 3 in the hundreds place (value of 300) has a value that is 10x the 3 in the tens (value of 30).

jeka57 [31]3 years ago

3 0

The correct answer is:

The 3 on the left is 10 times the value of the 3 on the right.

Explanation:

The 3 on the left is in the hundreds place. This makes its value 3(100) = 300.

The 3 on the right is in the tens place. This makes its value 3(10) = 30.

300/30 = 10; this means the 3 in the hundreds place is 10 times the value of the 3 in the tens place.

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3 years ago

What is 1110 x 234 and what is 2423 x 20397?

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Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

How do I solve this? -6x-1+5x^2 = 8x^2 Thanks

max2010maxim [7]

Answer:

$\displaystyle x=\frac{-3+\sqrt{6}}{3}\text{ and } x=\frac{-3-\sqrt{6}}{3}$

Or, by approximating:

$x\approx-0.1835\text{ or } x\approx -1.8165$

Step-by-step explanation:

Let’s convert this to standard form. We have:

$-6x-1+5x^2=8x^2$

Subtract 5x² from both sides:

$-6x-1=3x^2$

And add 6x and 1 to both sides:

$0=3x^2+6x+1$

This is not factorable. So, we will need to use the quadratic formula.

The quadratic formula for a quadratic in standard form is given by:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}$

In this case, a=3; b=6, and c=1.

Substitute appropriately:

$\displaystyle x=\frac{-6\pm\sqrt{6^2-4(3)(1)}}{2(3)}$

Simplify:

$\displaystyle x=\frac{-6\pm\sqrt{24}}{6}$

We can simplify the square root:

$\sqrt{24}=\sqrt{4}\cdot\sqrt{6}=2\sqrt{6}$

Hence:

$\displaystyle x=\frac{-6\pm2\sqrt{4}}{6}$

Simplify:

$\displaystyle x=\frac{-3\pm\sqrt{6}}{3}$

Hence, we will have two solutions:

$\displaystyle x=\frac{-3+\sqrt{6}}{3}\text{ and } x=\frac{-3-\sqrt{6}}{3}$

Approximating them, we can see that our solutions are approximately:

$x\approx-0.1835\text{ or } x\approx -1.8165$

7 0

3 years ago