circumference of a circle=2πr
area=πr²
1) we calculate the radius of this circle.
Data:
area=9π m²
area=πr²
9π m²=πr²
r²=9π m² / π
r²=9 m²
r=√(9 m²)=3 m
2) we calculate the circumference:
circumference=2πr=2π(3 m)=6π m
Answer: the circumference is 6π m
Answer:
24
Step-by-step explanation:
base (b) = 8
height (h) = 6
A = bh/2
= 8x6/2
= 48/2
= 24
Therefore the area is 24 square units
Answer:
state A = 32 votes, state B = 53 votes
Step-by-step explanation:
Let the number of electoral votes for state A be a and state B be b
a = b - 21
a + b = 85
Substituting a for b - 21 in the second equation
2b - 21 = 85
2b = 106
b = 53
Plugging b back in
85 - 53 = 32
The Pyth. Thm. applies here:
(√x + 1)^2 + (2√x)^2 = (2√x + 1 )^2
Expanding the squares:
x + 2sqrt(x) + 1 + 4x = 4x + 4sqrt(x) + 1
Let's subtract x + 2sqrt(x) + 1 + 4x from both sides:
4x + 4sqrt(x) + 1
-(x + 2sqrt(x) + 1 + 4x)
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3x + 2sqrt(x) - 4x = 0
Then 2sqrt(x) = x
Squaring both sides, 4x = x^2, or x^2 - 4x = 0. Then (x-4)x = 0, and the two possible solutions are 0 and 4.
Check these results by substitution. Does the Pyth. Thm. hold true for x=4?
