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victus00 [196]
3 years ago
9

The dimensions of a right rectangular prism are 0. 25 m, 0. 36 m, and 0. 14 m. What is the volume of the prism? Use the formula

V = ?X1 X/1.​
Mathematics
2 answers:
andrew11 [14]3 years ago
8 0

Answer:

7

Step-by-step explanation:

hopes it helps because this aas hard to do in my head

agasfer [191]3 years ago
6 0

Answer:

7

it can be confusing but read the formula closely

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elena-14-01-66 [18.8K]
The best order-of-magnitude estimate for 58,100:
C.10^5
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Evaluate the expression when a=-2 and x=7.<br> -2a+x
ziro4ka [17]

Step-by-step explanation:

-2a + x

Putting values of a = - 2 and x = 7

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2 years ago
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Vanessa is skiing along a circular ski trail that has a radius of 2.5 km. She starts at the 3-o'clock position and travels in th
yawa3891 [41]

Answer:

1.05 radians

Step-by-step explanation:

Given that Vanessa is skiing along a circular ski trail that has a radius of 2.5 km. She starts at the 3-o'clock position and travels in the Counter Clockwise direction.

She stops skiing when she is 1.244 km to the right and 2.169 km above the center of the ski trail.

This can be represented as (1.244, 2.169) on a circle of radius 2.5 km.

From the coordinate point (1.244, 2.169) derived, x=1.244 and y=2.169.

By the definition of tangent,

\tan \theta =\frac{y}{x} \\\\\tan \theta =\dfrac{2.169}{1.244}\\\\ \theta=\arctan \dfrac{2.169}{1.244}\\\\\\ \theta=1.05006

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3 0
3 years ago
Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas
lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

n(S) = n(s) + n(S \cap F)

In which n(s) are those who are succeful but not freshmen and n(S \cap F) are those who are succesful and freshmen.

By the same logic, we also have that:

n(F) = n(f) + n(S \cap F)

The union is:

n(S \cup F) = n(s) + n(f) + n(S \cap F)

In which

n(S \cup F) = 58

n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)

n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)

So

n(S \cup F) = n(s) + n(f) + n(S \cap F)

58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)

n(S \cap F) = 24

So the correct answer is:

b) 24

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Check this out that’s how it is I hope it helps

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