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Darina [25.2K]
3 years ago
7

19 less than 28 Write as a algebraic expression

Mathematics
2 answers:
pav-90 [236]3 years ago
8 0
Answer :

Choice A ) 28 - 19
boyakko [2]3 years ago
3 0

Answer:

A

Step-by-step explanation:

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The expression means 15 minus the product of 5 times the difference of p minus 6. If p = 8, then the value of the expression is
MA_775_DIABLO [31]

Answer:

5

Step-by-step explanation:

from the question:

15-5(p-6)

when p=8,

=15-5(8-6)

=15-5(2)

=15-10

=5

please like and Mark as brainliest

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3 years ago
Do you capitalize "is" after "!"<br> "HELLO!" is blah
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Y = 5+5(x-8)<br> Can someone please solve this?
vekshin1

y = 5+5(x-8)

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7 0
3 years ago
On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe
Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let <em>X</em> denote delivery time of the mail delivered by Alice and <em>Y</em> denote delivery time of the mail delivered by Bob.

It i provided that:

X\sim U(9, 11)\\Y\sim U(10, 12)

The probability that Alice delivers the mail is, <em>p</em> = 1/4.

The probability that Bob delivers the mail is, <em>q</em> = 3/4.

The probability density function of a Uniform distribution with parameters [<em>a</em>, <em>b</em>] is:

f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.

The probability density function of the delivery time of Alice is:

f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.

The probability density function of the delivery time of Bob is:

f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50

Thus, the value of fₓ (10.5) is 0.50.

5 0
3 years ago
PLZ help me it's is sooo hard
Andreas93 [3]
I'm not sure for number one, but for number 2 the answer to that one is the second tallest on the chart or on the histogram. For number 3 I'm not sure because i cant see the numbers there too blurry. I'm sorry but i hope i got the second one correct.
3 0
3 years ago
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