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Anettt [7]
3 years ago
11

Jackson is throwing a pizza party. He has 6\tfrac{1}{2}6 2 1 ​ pounds of cheese available and he needs \tfrac{1}{2} 2 1 ​ pound

of cheese to make each pizza. How many pizzas can he make?
Mathematics
2 answers:
andriy [413]3 years ago
6 0

He can make 8 pizzas because 4 x 1/2 is 8

adelina 88 [10]3 years ago
6 0

Answer:

8

Step-by-step explanati

4 x1/2=my awnser.

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Three times than five times a number​
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15

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2cos²x+2√2sinx-4=0<br> Giúp tôi với
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translate in eng

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3 years ago
Select two statements that are true about the equation y+4=-8(x-2)
bezimeni [28]

Answer:

Step-by-step explanation:

y + 4 = -8(x - 2)

I dont know the statements that u have but maybe I can guess one...or two

slope = -8

points used were : (2,-4)

y + 4 = -8(x - 2)

y + 4 = -8x + 16

y = -8x + 16 - 4

y = -8x + 12 ............slope intercept form

8x + y = 12 .......standard form

x intercept = (3/2,0)

y intercept = (0,12)

any of that answer ur question ?

5 0
3 years ago
Read 2 more answers
Integration questions .
dlinn [17]
<h2>1)</h2>

\\\\\ \textbf{a)}\\\\~~~\displaystyle \int (6x- \sin 3x) ~ dx\\\\=6\displaystyle \int x ~ dx - \displaystyle \int \sin 3x ~ dx\\\\=6 \cdot \dfrac{x^2}2 - \dfrac 13 (- \cos 3x) +C~~~~~~~~~~~;\left[\displaystyle \int x^n~ dx = \dfrac{x^{n+1}}{n+1}+C,~~~n \neq -1\right]\\\\ =3x^2 +\dfrac{\cos 3x}3 +C~~~~~~~~~~~~~~~~~~~~;\left[\displaystyle \int \sin (mx) ~dx = -\dfrac 1m ~ (\cos mx)+C \right]\\

\textbf{b)}\\\\~~~~\displaystyle \int(3e^{-2x} +\cos (0.5 x)) dx\\\\=3\displaystyle \int e^{-2x} ~dx+ \displaystyle \int \cos(0.5 x) ~dx\\\\\\=-\dfrac 32 e^{-2x} + \dfrac 1{0.5} \sin (0.5 x) +C~~~~~~~~~~~~~~;\left[\displaystyle \int e^{mx}~dx = \dfrac 1m e^{mx} +C \right]\\\\\\=-\dfrac 32 e^{-2x} + 2 \sin(0.5 x) +C~~~~~~~~~~~~~~~~~;\left[\displaystyle \int \cos(mx)~ dx  = \dfrac 1m \sin(mx) +C\right]\\\\\\=-1.5e^{-2x} +2\sin(0.5x) +C

<h2>2)</h2>

\textbf{a)}\\\\y = \displaystyle \int \cos(x+5) ~ dx\\\\\text{Let,}\\\\~~~~~~~u = x+5\\\\\implies \dfrac{du}{dx} = 1+0~~~~~~;[\text{Differentiate both sides.}]\\\\\implies \dfrac{du}{dx} = 1\\\\\implies du = dx\\\\\text{Now,}\\\\y= \displaystyle \int \cos u ~ du\\\\~~~= \sin u +C\\\\~~~=\sin(x+5) + C

\textbf{b)}\\\\y = \displaystyle \int 2(5x-3)^4 dx\\\\\text{Let,}\\~~~~~~~~u = 5x-3\\\\\implies \dfrac{du}{dx} = 5~~~~~~~~~~;[\text{Differentiate both sides}]\\\\\implies dx = \dfrac{du}5\\\\\text{Now,}\\\\y = 2\cdot \dfrac 1  5 \displaystyle \int u^4 ~ du\\\\\\~~=\dfrac 25 \cdot \dfrac{u^{4+1}}{4+1} +C\\\\\\~~=\dfrac 25 \cdot \dfrac{u^5}5+C\\\\\\~~=\dfrac{2u^5}{25}+C\\\\\\~~=\dfrac{2(5x-3)^5}{25}+C

<h2>3)</h2>

\textbf{a)}\\\\y =  \displaystyle \int xe^{3x} dx\\\\\text{We know that,}\\\\ \displaystyle \int  (uv) ~dx = u  \displaystyle \int  v ~ dx -  \displaystyle \int \left[ \dfrac{du}{dx} \displaystyle \int ~ v ~ dx \right]~ dx\\\\\text{Let}, u =x~ \text{and}~ v=e^{3x}  .\\\\y=  \displaystyle \int xe^{3x} ~dx\\\\\\~~=  x\displaystyle \int e^{3x} ~ dx -  \displaystyle \int  \left[\dfrac{d}{dx}(x)  \displaystyle \int  e^{3x}~ dx \right]~ dx\\\\\\

  =x\displaystyle \int e^{3x}~ dx  - \displaystyle \dfrac 13 \int \left(e^{3x} \right)~ dx\\\\\\=\dfrac{xe^{3x}}3 - \dfrac 13 \cdot \dfrac{ e^{3x}}3+C\\\\\\= \dfrac{xe^{3x}}{3}- \dfrac{e^{3x}}{9}+C\\\\\\=\dfrac{3xe^{3x}}{9}- \dfrac{e^{3x}}9 + C\\\\\\= \dfrac 19e^{3x}(3x-1)+C

 

<h2 />
8 0
2 years ago
What is the cost per pound? $5.48 for 4 pounds of grapes.
Agata [3.3K]

Answer:

$1.37/lb

Step-by-step explanation:

5.48/4

4 0
4 years ago
Read 2 more answers
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