Answer:
Ic² + b²l = 13 units.
Step-by-step explanation:
We have to evaluate the expression Ic² + b²l with unknowns b and c and having the values of b and c respectively - 3 and - 2.
Now, Ic² + b²l
= I(- 2)² + (- 3)²l {Putting the values of b and c}
= I4 + 9l
= I13l
= 13 units.
Therefore, Ic² + b²l = 13 units. (Answer)
Answer:
33) RQ
34) PQ
35) NO
36) MO
Step-by-step explanation:
3/2 = 9/x,
so 9 times 2 divided by 3 = 6
A: 6
Answer:
So basically anything higher than .5 would be x>.5 so it has to be greater than or equal to .51
Step-by-step explanation:
.51 .75 .89 .56 .78 .86 .61 it goes on and on as long as it is greater than .50
Answer:
x=-12
Step-by-step explanation:
(-22 + 3x) /( 3x+7) =2
Multiply each side of the equation by 3x+7
-22+3x = 2(3x+7)
Then distribute
-22 +3x = 6x+14
Subtract 3x from each side
-22 = 3x+14
Subtract 14 from each side
-36 = 3x
Divide by 3
-12 =x