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3 years ago

I’ll give BRAINLIEST to best answer, please answer fast.

Mathematics

1 answer:

Basile [38]3 years ago

3 0

2 waffles =3$

2x4=8 waffles (How many waffles Sage wants)

3 + 3 + 3 + 3= 12 (or 3x4)

(2) (4) (6) (8)

<u>12$ at I Scream</u>

4 waffles= 4$

4 waffles x2=8$

<u>8$ at Scoopz</u>

12-8= 4

<h3>Sage would save 4 dollars if she got 8 waffles at Scoopz.</h3>

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What is equivalent to the expression 9(z-6)

Liono4ka [1.6K]

Using the distributive property an equivalent expression would be 9z-54

6 0

3 years ago

Read 2 more answers

A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v

BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: <u>Confidence</u> <u>Interval</u> is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

$p_{1}=\frac{30}{120}=0.25$

$p_{2}=\frac{32}{160}=0.2$

Second, calculate standard deviation for each proportion:

$\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395$

$\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316$

Now, we calculate standard error for difference:

$SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}$

$SE=\sqrt{0.0395^{2}+0.0316^{2}}$

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

$p_{1}-p_{2}$ ± z-score.SE

$0.25-0.2$ ± $1.645(0.0505)$

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = $-0.0332$

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is $[-0.0332,0.1332]$ .

8 0

3 years ago

20 POINTS!!!!! (Voting Brainiest) Two Math Problems!!

Murljashka [212]

Y= 14

(4,-2)

hope that helps

7 0

3 years ago

Read 2 more answers

PLEASE HELP

lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function $j\left(x\right) \ = \ 4^{x-2}$ , hence the average rate of change (slope of the blue line) between the $x$ and $x+h$ is

$\text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}$

$\\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}$

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2 years ago

A basket of laundry is being separated. Divide 48 pieces of clothing into 2 groups so that the ratio is 1:3

Alla [95]

Ratio is 1:3.....added = 4

1/4(48) = 48/4 = 12
3/4(48) = 144/4 = 36

the 2 groups will be 12 and 36

5 0

3 years ago