Question

PLEASE HELP!!

Answer 1

Answer:

-1 and -3

(n+7)(n-8)

Step-by-step explanation:

1. Find the Zeros

$f(x)=x^{2} +4x+3$

$f(x)=\left(x+1\right)\left(x+3\right)$

$x+1=0\\x=-1\\x+3=0\\x=-3$

2. Factoring Trinomials

$f(x)=n^{2} -n-56$

$f(x)=\left(n+7\right)\left(n-8\right)$

$n+7=0\\n=-7\\n-8=0\\n=8$