Answer:
160
Explanation:
If p = frequency of dominant allele and q = frequency of recessive allele according to Hardy-Weinberg equilibrium,
p + q = 1
p² + 2pq + q² = 1
where p² = frequency of dominant homozygous genotype
q² = frequency of recessive homozygous genotype
2pq = frequency of heterozygous genotype
Here,
b = 4% = 0.04
bb = 0.04 * 0.04 = 0.0016
Number of individuals in population = 100000
Number of homozygous bb individuals = 0.0016 * 100000 = 160
yes the trees maintain the balance between gases in the air
The male fruit fly has an XY profile of the sex chromosomes, and the female has an XX profile of the sex chromosomes.
If a male is white-eyed, then it must have a white recessive allele on his only X chromosome and the red eyed female can be homozygous (having two dominant red eye alleles) or heterozygous (having both a dominant and a recessive allele).
If the female is homozygous then all of the offspring will be red-eyed, and if she's heterozygous then half of the offspring will be white eyed. (see the table provided below)