So first what we do is we need to get the excluded values. So to get them we have: 8x^4/x^3+7x^4.
Lets factor out the second part. x^3+7x^4 = (x^(3/4)+7x))^4
So then we get 8x^4/(x^(3/4)+7x)^4
8x^4/(x^(3/4)+7x)^4
Answer:
here u go
Step-by-step explanation:
16
/5 =3 and 1 over 53 1
/5=3.2
Any number multiplied by one keeps its identity
