Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
Answer: 13+16x
Step-by-step explanation:
Okay so I just learned how to do that haha, so if the answer is wrongdoing I'm a sorry.
I added the 8 and five, then multiplyed the 4 and the 4 then added the x on the end.
Answer:
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$68,684
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Step-by-step explanation:
Answer:
It is not
mark as brainliest plz :)
In standard form it would be 2x - 3y = 3
